Another Ages Problem

The sum of the ages of four children of a family is equal to one half of their father's age. The difference of the squares of the ages of the oldest and youngest child equals the father's age which is also equal to twice the sum of the differences of the squares of the ages of the two younger and two older children. In 16 years, the sum of the ages of the children will exceed the father's age by his present age. How old are the fatehr and the four children?

Originally posted by phgao
The sum of the ages of four children of a family is equal to one half of their father's age. The difference of the squares of the ages of the oldest and youngest child equals the father's age which is also equal to twice the sum of the differences of the squares of the ages of the two younger and two older children. In 16 years, the sum of the ages of the ch ...[text shortened]... will exceed the father's age by his present age. How old are the fatehr and the four children?

Originally posted by Mephisto2
Father = 32
Children: 2, 3, 5 & 6

Originally posted by kody magic
That doesn't work for the 16 years time scenario, though.

Good point. That'll teach me to read the question properly!

Originally posted by Mephisto2
Father = 32
Children: 2, 3, 5 & 6