Originally posted by lausey
Think I know what you are describing. The balloon would actually move towards the axis of rotation. The air would increase in pressure at the end of the cylinder (end as in direction away from the axis of rotation). The balloon would oppose this force due to gas bouyancy (tend towards the axis of rotation where the air density would be less). This is because ...[text shortened]... d. Not related to the current scenario in this thread but still a point I needed to correct. 😀
Give the man the golden ring! Thats what would happen. I told this
one to my son Kevin and he had the answer before I could even
finish telling it. He is used to my puzzles by now.
I had one where the same kind of cylinder was on a space ship
way away from stuff so basically at zero gravity and then you do the
same thing, put a balloon dead center, then fire a rocket at one end.
What happens to the balloon? Same thing, If it were a bowling ball
it would go to the end where the rocket is of course but a helium
balloon goes the other way for just the reason you said:
pressure differential is what gives the lifting force so I was pointing
out what Einstein said a long time ago: you can't tell the differance
between gravitation and acceleration so if you take the cylinder and
just hold it upright, gravity does the pressure gradient, if you spin it,
centripital does it, if you fire up a rocket, acceleration does it.
All three ways end up with a pressure gradient. I think I have run this
one into the ground!