Another math problem 3

Boos 1 and boos 2, gave me each one 30(60 total) melons to sell them at the market with one condition:

Boos 1: sets his price 3 per 1 dollar
Boos 2: sets his price 2 per 1 dollar

So logically, boss 1 will receive 10 dollars for his 30 melons, and boss 2 will receive 15, for a total of 25 dollars.

The melons looked alike, so if I started selling 3 per dollar and then 2 per dollar, the last customers will think that I overpriced them, and wont buy, and if I sell 2 per dollar first, and then 3 per dollar, the first customers will think that I cheated on them.

Based on that I made the following solution, I will put the melons together, and sell them 5 melons per 2 dollars, that way I sell 3 per 1 and 2 per 1 at the same time.

By the time I ended selling the melons I obtained 24 dollars, and I don’t know why because I sold them with extra care and there was no mistake, so How I’m I going to explain the missing dollar?

Originally posted by Superman
Boos 1 and boos 2, gave me each one 30(60 total) melons to sell them at the market with one condition:

Boos 1: sets his price 3 per 1 dollar
Boos 2: sets his price 2 per 1 dollar

So logically, boss 1 will receive 10 dollars for his 30 melons, and boss 2 will receive 15, for a total of 25 dollars.

The melons looked alike, so if I started selling 3 ...[text shortened]... them with extra care and there was no mistake, so How I’m I going to explain the missing dollar?

Tell them you set the price wrong.

If you sell 30 melons for $0.50 each, and 30 for $0.333 each, generating $25 in revenue, the average price ends up being $25/60 = $0.42. However, if you sold all 60 melons for $24, then the average price ends up being $24/60 = $0.40.

This happens because when you sell 5 melons together and just add the individual costs, you end up selling (2/5)*60 = 24 expensive melons and (3/5)*60 = 36 cheap ones. This drags the average price down.

Originally posted by Superman
Boos 1 and boos 2, gave me each one 30(60 total) melons to sell them at the market with one condition:

Boos 1: sets his price 3 per 1 dollar
Boos 2: sets his price 2 per 1 dollar

So logically, boss 1 will receive 10 dollars for his 30 melons, and boss 2 will receive 15, for a total of 25 dollars.

The melons looked alike, so if I started selling 3 ...[text shortened]... them with extra care and there was no mistake, so How I’m I going to explain the missing dollar?

Because the average price is not the same.

The requested average price = (1/3 +1/2)/2 = 5/12 dollar, leading to a total of 5/12 x 60 = 25 dollars

The 'solution' average price = 2/5 dollar, leading to 2/5 x 60 = 24 dollars.

How do u get your puzzel online

Originally posted by TheChessKing
How do u get your puzzel online

I have a few books.