1. Joined
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    01 Jul '20 21:421 edit
    @joe-shmo

    That's probability, more than 'racing'

    In ratio 4 : 2 : 1 for A,B,C

    So A is 4/7 ,( B is 2/7 and C is 1/7)
  2. R
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    01 Jul '20 22:06
    @blood-on-the-tracks said
    @joe-shmo

    That's probability, more than 'racing'

    In ratio 4 : 2 : 1 for A,B,C

    So A is 4/7 ,( B is 2/7 and C is 1/7)
    Lol. @blood-on-the-tracks.

    You got me, but it was phrased in the context of racing so I thought I'd sneak it in!

    Good Job!
  3. R
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    01 Jul '20 22:09
    Here is another "probability" question "about racing".

    For a 100-meter race, Adam’s race time ranges from 10-12 seconds, and Benjamin’s ranges from 11-13 seconds. Both times are independent and uniformly distributed.
    If Adam and Benjamin run a 100-meter race together, what is the probability that Adam wins?
    Also: The probability of a tie is again 0.
  4. Joined
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    01 Jul '20 23:52
    @joe-shmo

    Thought it through twice. I will say 1/8 or .125
  5. R
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    02 Jul '20 00:20
    @eladar said
    @joe-shmo

    Thought it through twice. I will say 1/8 or .125
    No Sir. Have another think.
  6. Standard memberwolfgang59
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    02 Jul '20 00:34
    @joe-shmo said
    Bob, John and Josh are running a 1 km race. Each competitor runs at a constant rate.

    After Bob has run 1/4 km, Bob is ahead of John by 25 meters.
    After John has run 1/2 km, John is ahead of Josh by 20 meters.

    When Bob finishes the race, by how much distance does he beat Josh?
    When Bob has run 1,000m he is ahead of John by 25m x 1,000/250 = 100m

    When John has run 900m he is ahead of Josh by 20m x 900/500 = 36m

    So when Bob finishes he is 136m ahead of Josh. Well done Bob!
  7. R
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    02 Jul '20 00:351 edit
    @wolfgang59 said
    When Bob has run 1,000m he is ahead of John by 25m x 1,000/250 = 100m

    When John has run 900m he is ahead of Josh by 20m x 900/500 = 36m

    So when Bob finishes he is 136m ahead of Josh. Well done Bob!
    @wolfgang59

    Late to the party, but yes. that is correct!

    There is still an open "racing" probability question above if your interested.
  8. Standard memberwolfgang59
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    02 Jul '20 00:43
    @joe-shmo said
    Here is another "probability" question "about racing".

    For a 100-meter race, Adam’s race time ranges from 10-12 seconds, and Benjamin’s ranges from 11-13 seconds. Both times are independent and uniformly distributed.
    If Adam and Benjamin run a 100-meter race together, what is the probability that Adam wins?
    Also: The probability of a tie is again 0.
    If Adam runs sub 11 seconds he wins (that is 1/2 chance)
    If Adam runs slower then he wins if Bob runs slower than 12 seconds. (That is 1/2 * 1/2 = 1/4 chance)

    If the both run between 11 and 12 seconds they have evens chance of winning.
    (1/2 * 1/2 * 1/2)

    Total that all up 1/2 + 1/4 + 1/8 = 7/8
  9. Standard memberwolfgang59
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    02 Jul '20 00:44
    @joe-shmo said
    @wolfgang59

    Late to the party, but yes. that is correct!

    There is still an open "racing" probability question above if your interested.
    LOL
    Didn't hit post when I typed it earlier today!
  10. R
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    02 Jul '20 00:45
    @wolfgang59 said
    If Adam runs sub 11 seconds he wins (that is 1/2 chance)
    If Adam runs slower then he wins if Bob runs slower than 12 seconds. (That is 1/2 * 1/2 = 1/4 chance)

    If the both run between 11 and 12 seconds they have evens chance of winning.
    (1/2 * 1/2 * 1/2)

    Total that all up 1/2 + 1/4 + 1/8 = 7/8
    That is correct!
  11. R
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    02 Jul '20 00:46
    @wolfgang59 said
    LOL
    Didn't hit post when I typed it earlier today!
    Ahh..so early to the party..just side tracked. 🙂
  12. R
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    02 Jul '20 00:471 edit
    @wolfgang59 said
    If Adam runs sub 11 seconds he wins (that is 1/2 chance)
    If Adam runs slower then he wins if Bob runs slower than 12 seconds. (That is 1/2 * 1/2 = 1/4 chance)

    If the both run between 11 and 12 seconds they have evens chance of winning.
    (1/2 * 1/2 * 1/2)

    Total that all up 1/2 + 1/4 + 1/8 = 7/8
    P.S. "Bob" is running in a different race!
  13. Standard memberwolfgang59
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    02 Jul '20 00:51
    @joe-shmo said
    P.S. "Bob" is running in a different race!
    Ha!
    My teacher always said READ THE QUESTION CAREFULLY
  14. R
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    02 Jul '20 01:00
    Continuing with Racing Theme:

    In order to determine the starting position of a racer in NASCAR time trials are performed where the racer make a series of laps around a track. Each racer is ranked according to the total average speed of the laps ( i.e total distance traveled over total time to complete the laps ).

    Suppose a racer is performing a two lap time trial and their target average speed for the trial is 181 mph. On their first lap they suffer a spin out, and end up only averaging 90 mph. At what average speed must they travel over the final lap to achieve the target 181 mph average speed for both laps?
  15. Standard memberwolfgang59
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    02 Jul '20 01:03
    @joe-shmo said
    Continuing with Racing Theme:

    In order to determine the starting position of a racer in NASCAR time trials are performed where the racer make a series of laps around a track. Each racer is ranked according to the total average speed of the laps ( i.e total distance traveled over total time to complete the laps ).

    Suppose a racer is performing a two lap time trial and ...[text shortened]... speed must they travel over the final lap to achieve the target 181 mph average speed for both laps?
    Even c wouldn't cut it!
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