Originally posted by glandmaster flashlots of drill holes? ha ha.... just wanted to look at it from a non-scientific angle.😀
Apologies if posted previously.
A freestanding 25kgs barrell is filled with something that immediately makes it weigh just 15 kgs.What has it been filled with to make it lighter than before?
Originally posted by glandmaster flashExactly 10kg of antimatter (because 10kg of antimatter will immediately annulated exactly 10kg of matter that makes up the barrel).
Apologies if posted previously.
A freestanding 25kgs barrell is filled with something that immediately makes it weigh just 15 kgs.What has it been filled with to make it lighter than before?
-but the problem with that answer is that, by the time the interaction is complete, what is left of the barrel will be immediately vaporised thus you will be left with no barrel.
Originally posted by glandmaster flashThis is a question that has to be treated scientifically, if it's not just a trick question or joke problem.
A freestanding 25kgs barrell is filled with something that immediately makes it weigh just 15 kgs.What has it been filled with to make it lighter than before?
A can accept that a barrell can have a mass of 25 kg.
But I cannot accept that this barrel (after the reduction) can weigh 15 kg.
Kilogram is the unit of mass, not of weight.
The unit of weight is Newton, on the other hand, because it is a force.
Do you mean that the barrel has lost a mass of 10 kg? Or is this a part of the joke or trick that mass is converted to a force?
Originally posted by Andrew HamiltonThe mass of elementary particles varies quite a bit, so in antimatter-matter-reactions energy will be converted to mass and mass to energy on quite a large scale. So the final mass of the barrel will depend on what antimatter you're reacting with what matter and what the energy of the antimatter and matter is.
How so?
-I have studied physics at university and I have never heard of this one.
Originally posted by KazetNagorraI am not sure but I think I see what you mean -if a positron meets either a neutron then, despite the fact that the positron has only a fraction of the mass of a neutron, does both all the mass of the positron and ALL the mass of the neutron get converted into energy?
The mass of elementary particles varies quite a bit, so in antimatter-matter-reactions energy will be converted to mass and mass to energy on quite a large scale. So the final mass of the barrel will depend on what antimatter you're reacting with what matter and what the energy of the antimatter and matter is.
Also, I forgot that, because of the nuclear binding energy is different for each isotope for each chemical element, the number of nucleons an atom has is not exactly proportional to its mass (I am assuming here that all the atoms have their full compliment of electrons and are not ionised). So this would mean that the amount of energy released from, say, 4 hydrogen atoms colliding with 4 anti-hydrogen atoms would be a bit different from amount of energy released from, say, 4 hydrogen atoms colliding with a single anti-helium-4 atom.
Ok -but there is a way around this:
Exactly 10kg of antimatter of a type that is the exact antimatter equivalent of the same type of material the barrel is made of (for example, if the barrel is made of pure iron-52 isotope then the antimatter must be pure anti-iron-52 isotope) will annulated almost exactly 10kg of the mass of the barrel (although you will still be left with no barrel).