- 09 Feb '11 12:1918,446,744,073,709,551,615 grains of rice weighing 461,168,602,000 tons. (thank you Wiki).

Now this is Swiss Gambit territory.

At the start of a game using the beginner formula.

Queen = 9

Rook = 5

Bishop = 3

Knight = 3

Pawn = 1

After winning a bet the loser askes you to contruct a game saying he wiil

give you £1.00 in value for every piece left on the board, both Black and White

at the time of checkmate.

You agree. What is the most amount of money you can score?

Basically how many possible pawn promotions (thus making £1 = £9)

can you squeeze out of a game of chess? - 09 Feb '11 12:33

so the guy will give you a dollar for every point?*Originally posted by greenpawn34***18,446,744,073,709,551,615 grains of rice weighing 461,168,602,000 tons. (thank you Wiki).**

Now this is Swiss Gambit territory.

At the start of a game using the beginner formula.

Queen = 9

Rook = 5

Bishop = 3

Knight = 3

Pawn = 1

After winning a bet the loser askes you to contruct a game saying he wiil

give you £1.00 in value for every ...[text shortened]... how many possible pawn promotions (thus making £1 = £9)

can you squeeze out of a game of chess? - 09 Feb '11 17:43

That's exactly what I mean-*Originally posted by dogfish44***No, because if you do EVERY single combination facing 1 way, the others oon the other sides are already done.**

2^64 is correct.

so you'd have some redundant combinations because they are just "flipped" images of each other so 2^64 is too many.

Just think of one the corner squares as black, the rest as white. This accounts for 4 different sets, flip it 90 degrees and you'll end up with a different corner as black. This one coloring scheme accounts for 4 combinations - 09 Feb '11 19:19
*Originally posted by greenpawn34***18,446,744,073,709,551,615 grains of rice weighing 461,168,602,000 tons. (thank you Wiki).**

Now this is Swiss Gambit territory.

At the start of a game using the beginner formula.

Queen = 9

Rook = 5

Bishop = 3

Knight = 3

Pawn = 1

After winning a bet the loser askes you to contruct a game saying he wiil

give you £1.00 in value for every ...[text shortened]... how many possible pawn promotions (thus making £1 = £9)

can you squeeze out of a game of chess?You can promote every pawn on the board, but you must capture all the minor pieces. 9 x 9 Queens + 2 x 2 Rooks = 91 points. This multiplied by 2 armies = 182 points = £182 - 09 Feb '11 22:34 / 5 edits

To solve the problem when rotation of the board is allowed but flipping (i.e. mirror images) are not:*Originally posted by ua41***That's exactly what I mean-**

so you'd have some redundant combinations because they are just "flipped" images of each other so 2^64 is too many.

Just think of one the corner squares as black, the rest as white. This accounts for 4 different sets, flip it 90 degrees and you'll end up with a different corner as black. This one coloring scheme accounts for 4 combinations

Count the number of fixed boards with 90 degree rotational symmetry. One corner of the board with 16 squares determines the rest: 2^16.

Count the number of fixed boards with 180 degree rotational symmetry that don't also have 90 degree rotational symmetry. One half of the board with 32 squares determines the rest, but subtract out the ones counted for 90 degree rotation: 2^32 - 2^16. So that we don't count each of these twice when we remove rotations in the final tally (once with no rotation and again with a 90 degree rotation), divide this number by 2.

Count the number of fixed boards with 360 degree rotational symmetry that don't also have 90 degree or 180 degree rotational symmetry: 2^64 - (2^32 - 2^16) - (2^16). So that we don't count each of these four times when we remove rotations in the final tally (once with no rotation and again with 90, 180, and 270), divide this number by 4.

Add up the three terms and simplify:

2^16 + (2^32 - 2^16)/2 + (2^64 - 2^32)/4

2^16 + 2^31 - 2^15 + 2^62 - 2^30

2^62 + (2^30)(2-1) + (2^15)(2-1)**2^62 + 2^30 + 2^15 = 4,611,686,017,353,613,312**

This is essentially the same as ignoring the relatively few positions with rotational symmetry and doing (2^64)/4 = 2^62 = 4,611,686,018,427,387,904 which is identical up to the 10th digit.

This method seems sound to me, but I might have miscounted somewhere. - 11 Feb '11 04:15

My God, why must everything be over-analyzed and complicated?? Do you flip the board or rotate it when you play chess? NO. Then just solve the problem as if it was a chessboard glued to the table in front of you. Jeeeez.*Originally posted by Arctic Penguin***[quote]***Originally posted by ua41*

[b]That's exactly what I mean-

so you'd have some redundant combinations because they are just "flipped" images of each other so 2^64 is too many.

Just think of one the corner squares as black, the rest as white. This accounts for 4 different sets, flip it 90 degrees and you'll end up with a different corne ...[text shortened]... he 10th digit.

This method seems sound to me, but I might have miscounted somewhere. - 11 Feb '11 05:05 / 9 edits

Most chess boards I've seen don't specify which end is for black and which end is for white, so yes it probably does get rotated between games. The puzzle is a bit too simple if the board is just fixed to the table, don't you think?*Originally posted by Bebop5***My God, why must everything be over-analyzed and complicated?? Do you flip the board or rotate it when you play chess? NO. Then just solve the problem as if it was a chessboard glued to the table in front of you. Jeeeez.**