Posers and Puzzles
21 Dec 13
21 Dec 13
So on an ordinary 12 hour clock, draw 2 lines between any set of numbers, from outside to inside, that is, intersecting a circle surrounding the numbers, say a line from the space between 7 and 8 and continuing to the space between 3 and 4, that kind of thing.
If the lines don't intersect, you have 3 spaces, if they intersect you have 4 spaces defined.
The puzzle is to place the lines in such a way that the addition of the resultant numbers are all equal.
23 Dec 13
Originally posted by sonhouseSince the sum of 1 to 12 is 78 and 78/3=26:
So on an ordinary 12 hour clock, draw 2 lines between any set of numbers, from outside to inside, that is, intersecting a circle surrounding the numbers, say a line from the space between 7 and 8 and continuing to the space between 3 and 4, that kind of thing.
If the lines don't intersect, you have 3 spaces, if they intersect you have 4 spaces defined. ...[text shortened]... le is to place the lines in such a way that the addition of the resultant numbers are all equal.
One field with 11,12,1,2
one field with 10,9,3,4
and 5,6,7,8
23 Dec 13
1 edit
Originally posted by PonderableBingo! Tip o the hat to ye! Yep, you could see clearly it had to be a three partition, 4 would been 19.5 X4 =78. So the lines could never intersect leaving only a triple partition.
Since the sum of 1 to 12 is 78 and 78/3=26:
One field with 11,12,1,2
one field with 10,9,3,4
and 5,6,7,8
