coins

a blind man is alone in a room with 100 coins. 90 are heads, 10 are tails. he cannot feel which ones are heads or tails. how can he get two piles of coins with an equal number of tails in each pile?

What is a blind man doing in a room on his own? Is the door open or has he been locked in? 'Cos that contravenes health and safety regulations. If he can find an exit, he can just take all the coins and be well rich!

good point

Originally posted by genius
a blind man is alone in a room with 100 coins. 90 are heads, 10 are tails. he cannot feel which ones are heads or tails. how can he get two piles of coins with an equal number of tails in each pile?

Originally posted by genius
a blind man is alone in a room with 100 coins. 90 are heads, 10 are tails. he cannot feel which ones are heads or tails. how can he get two piles of coins with an equal number of tails in each pile?

Originally posted by trekkie
Turn 10 coins. Then create two piles of ten coins.


I think !!! 😕

It is only possible if he has two piles of no coins

Originally posted by Mock True
It is only possible if he has two piles of no coins

Originally posted by genius
no-it is perfectly poissible. if you want i can post the answer...it's one of these problems that you either see it at first, or usually don't see it...and trekkie-u are almost there!...

Originally posted by Acolyte
Haven't you already posted a very similar puzzle? Anyway, the answer is he spilts the coins 90/10 and turns over the coins in the smaller pile.

D'oh!!!

Originally posted by genius
yeah-that's right. i wasn't sure if i'd posted it before, so i posted it anyway 😀 i probubly did...

Originally posted by genius
a blind man is alone in a room with 100 coins. 90 are heads, 10 are tails. he cannot feel which ones are heads or tails. how can he get two piles of coins with an equal number of tails in each pile?