Distance = Time x Speed (Extremely Easy)

GinoJ
Posers and Puzzles 19 Feb '07 19:20
1. 19 Feb '07 19:20
As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.
2. PBE6
Bananarama
19 Feb '07 19:46
Originally posted by GinoJ
As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.
Let "w" be the walking speed in miles/hour. Then:

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph
3. 19 Feb '07 19:52
3 mph and 6 mph
4. 19 Feb '07 20:131 edit
Originally posted by Mephisto2
3 mph and 6 mph
Correct.

5. 19 Feb '07 20:22
I'm retired ðŸ˜€

Vw x Tw = 2 => Tw = 2 / Vw

Vj x Tj = 2
Vj = 2 Vw => Vw x Tj = 1 => Tj = 1 / Vw

Tw + Tj = 1 => 2 / Vw + 1 / Vw = 1 => Vw = 3 and Vj = 6
6. 19 Feb '07 20:25
Originally posted by PBE6
Let "w" be the walking speed in miles/hour. Then:

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph
Incorrect ðŸ˜›, the answer is 3 and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.
7. PBE6
Bananarama
19 Feb '07 20:27
Originally posted by GinoJ
Incorrect ðŸ˜›, the answer is 3 [b]and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.[/b]
Although I did miss the part of the question where you asked for both speeds, I don't need a physics lesson. ðŸ˜›
8. uzless
The So Fist
20 Feb '07 18:041 edit
Originally posted by GinoJ
Incorrect ðŸ˜›, the answer is 3 [b]and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.[/b]
Hey, what's the big idea?

You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.
9. 20 Feb '07 19:26
Originally posted by uzless
Hey, what's the big idea?

You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.
...and?
10. uzless
The So Fist
20 Feb '07 20:42
Originally posted by GinoJ
...and?
I suppose you could make an argument for locality being sufficiently small enough and application trumping derivation for the purposes of the equation.

3 and 6