19 Feb 07
Originally posted by GinoJLet "w" be the walking speed in miles/hour. Then:
As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.
2/w + 2/(2*w) = 1
3/w = 1
w = 3 mph
19 Feb 07
Originally posted by PBE6Incorrect 😛, the answer is 3 and 6.
Let "w" be the walking speed in miles/hour. Then:
2/w + 2/(2*w) = 1
3/w = 1
w = 3 mph
SOLUTION:
We'll use the basic Time= Distance/Speed formula.
Let the speed (or walking or jogging rate) be x.
a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time
So;
2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6
3 is the walking rate.
6 is the jogging rate.
19 Feb 07
Originally posted by GinoJAlthough I did miss the part of the question where you asked for both speeds, I don't need a physics lesson. 😛
Incorrect 😛, the answer is 3 [b]and 6.
SOLUTION:
We'll use the basic Time= Distance/Speed formula.
Let the speed (or walking or jogging rate) be x.
a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time
So;
2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6
3 is the walking rate.
6 is the jogging rate.[/b]
20 Feb 07
1 edit
Originally posted by GinoJHey, what's the big idea?
Incorrect 😛, the answer is 3 [b]and 6.
SOLUTION:
We'll use the basic Time= Distance/Speed formula.
Let the speed (or walking or jogging rate) be x.
a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time
So;
2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6
3 is the walking rate.
6 is the jogging rate.[/b]
You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.