Distance = Time x Speed (Extremely Easy)

As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.

Originally posted by GinoJ
As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.

Let "w" be the walking speed in miles/hour. Then:

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph

3 mph and 6 mph

Originally posted by Mephisto2
3 mph and 6 mph

Correct.

[edit] Show your work please.

I'm retired 😀

Vw x Tw = 2 => Tw = 2 / Vw

Vj x Tj = 2
Vj = 2 Vw => Vw x Tj = 1 => Tj = 1 / Vw

Tw + Tj = 1 => 2 / Vw + 1 / Vw = 1 => Vw = 3 and Vj = 6

Originally posted by PBE6
Let "w" be the walking speed in miles/hour. Then:

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph

Incorrect 😛, the answer is 3 and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.

Originally posted by GinoJ
Incorrect 😛, the answer is 3 [b]and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.[/b]

Although I did miss the part of the question where you asked for both speeds, I don't need a physics lesson. 😛

Originally posted by GinoJ
Incorrect 😛, the answer is 3 [b]and 6.

SOLUTION:

We'll use the basic Time= Distance/Speed formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate
b) 2/2x = Jogging Rate
c) 1 hour = Time

So;

2/x + 2/2x =1
6/2x = 1
x = 3
2x = 6

3 is the walking rate.
6 is the jogging rate.[/b]

Hey, what's the big idea?

You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.

Originally posted by uzless
Hey, what's the big idea?

You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.

...and?

Originally posted by GinoJ
...and?

I suppose you could make an argument for locality being sufficiently small enough and application trumping derivation for the purposes of the equation.

3 and 6