- 19 Feb '07 19:46

Let "w" be the walking speed in miles/hour. Then:*Originally posted by GinoJ***As a part of your exercise regimen, you walk 2 miles on an indoor track. Then you jog at twice of your walking speed for another 2 miles. If the total time spent walking and jogging is 1 hour, find the walking and jogging rates and show your solution.**

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph - 19 Feb '07 20:25

Incorrect , the answer is 3*Originally posted by PBE6***Let "w" be the walking speed in miles/hour. Then:**

2/w + 2/(2*w) = 1

3/w = 1

w = 3 mph**and 6**.

**SOLUTION:**

We'll use the basic*Time= Distance/Speed*formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate

b) 2/2x = Jogging Rate

c) 1 hour = Time

So;

2/x + 2/2x =1

6/2x = 1

x = 3

2x = 6

**3**is the walking rate.**6**is the jogging rate. - 19 Feb '07 20:27

Although I did miss the part of the question where you asked for both speeds, I don't need a physics lesson.*Originally posted by GinoJ***Incorrect , the answer is 3 [b]and 6**.

**SOLUTION:**

We'll use the basic*Time= Distance/Speed*formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate

b) 2/2x = Jogging Rate

c) 1 hour = Time

So;

2/x + 2/2x =1

6/2x = 1

x = 3

2x = 6

**3**is the walking rate.**6**is the jogging rate.[/b] - 20 Feb '07 18:04 / 1 edit

Hey, what's the big idea?*Originally posted by GinoJ***Incorrect , the answer is 3 [b]and 6**.

**SOLUTION:**

We'll use the basic*Time= Distance/Speed*formula.

Let the speed (or walking or jogging rate) be x.

a) 2/x = Walking Rate

b) 2/2x = Jogging Rate

c) 1 hour = Time

So;

2/x + 2/2x =1

6/2x = 1

x = 3

2x = 6

**3**is the walking rate.**6**is the jogging rate.[/b]

You haven't stated what your inertial frame is. Without a frame, you cannot judge time and motion since you have not proven whether or not free bodies exist.