- 28 Oct '11 05:03 / 1 edit

I'll say*Originally posted by talzamir***A drinking glass has a round base with radius r1, height of h and radius r2 > r1 at the upper rim. On its side on the table the glass goes around in a circle. How many full rotations does the glass do during one such circle?**

Theta = 2*pi*(r2-r1)/h

Theta = 2*pi

so number of rotations is

N = (r2-r1)/h - 28 Oct '11 05:37

I do not think your answer will yield the right trends with respect to parameter variations. For example, consider if (r2-r1) becomes very small (for some constant h). N should get very big because the glass will sweep out a very large circle, right?*Originally posted by joe shmo***I'll say**

Theta = 2*pi*(r2-r1)/h

Theta = 2*pi

so number of rotations is

N = (r2-r1)/h - 28 Oct '11 05:50

yeah...I suppose so. I did it hastily while I'm slightly under the influence...sorry*Originally posted by LemonJello***I do not think your answer will yield the right trends with respect to parameter variations. For example, consider if (r2-r1) becomes very small (for some constant h). N should get very big because the glass will sweep out a very large circle, right?**