25 Jan '07 01:07

What is the area of the largest square that you can draw in a cricle which has a radius of 4 meters?

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25 Jan '07 19:575 edits

Actually I do not understand how you get it. I am sure you did the same as below.*Originally posted by kbaumen***Yep, easy as a pie. A side of the square equals radius time square root of 2 (4 * sqrt(2)) and (4*sqrt(2))² = 16 * 2 = 32.**

The solution is:

1) Draw a square in a circle which has radius of 4.

2) Divide it into two triangles from the corners of the square, both triangles will be sharing the same hypotenuse.

3) The hypotenuse is 8 meters since the diameter of the circle is 8. Note that the other sides of the triangles are same since the square has 4 same sides.

5) So; we need to solve it from the pythagoras formula: a²=b²+c². We know ''a'' is 8 and we know ''b'' and ''c '' are the same. So, let b and c be X as one side of the square or the same sides of the triangles.

8²= 2x²

2x²= 64

x² = 32

x = Square Root 32m

5) Finally, we know one side of the square. The answer is:

A= (Square Root 32m)x(Square Root 32m)

A= 32m²

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Sigulda, Latvia28 Jan '07 09:202 edits

Yep, I did the same. (without mentioning the pythagorean) In a square it's side line is equal with the half diagonal times squareroot of 2. If it's a cube, then the side line is equal with the half diagonal times squareroot of 3.*Originally posted by GinoJ***Actually I do not understand how you get it. I am sure you did the same as below.**

The solution is:

1) Draw a square in a circle which has radius of 4.

2) Divide it into two triangles from the corners of the square, both triangles will be sharing the same hypotenuse.

3) The hypotenuse is 8 meters since the diameter of the circle is 8. Note that the ------------------------------------------------------------

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