Originally posted by GinoJ
A player has 12 hits after 40 times a bat. How many additional consecutive times must the player hit the ball to achieve a batting avarage of 0.440?
Show your solution.
I don't know much about baseball (and even less about "eeze baseball", whatever that may be), but let's assume that you want the number of hits divided by the number of goes to be 0.440
So (12+x)/(40+x) = 0.440
where x is the number of extra goes.
Solving for x gives 10.
Is this what you were after?
[edit: OK - in the time it took me to type this the question was answered!]