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eeze baseball question

eeze baseball question

Posers and Puzzles

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A player has 12 hits after 40 times a bat. How many additional consecutive times must the player hit the ball to achieve a batting avarage of 0.440?

Show your solution.

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0.0440 or 0.440 ?

2 edits
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Originally posted by aging blitzer
0.0440 or 0.440 ?
Are you blind?

It writes 0.440 there

You have aged so much, you can't see numbers now. ๐Ÿ˜›

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(n+12) / (n+40) = 0.44

n + 12 = 0.44 * (n + 40)

n + 12 = 0.44n + 0.44*40

n(1 - 0.44) = 0.44*40 - 12

n = (0.44*40 - 12) / (1 - 0.44)

n = 5.6 / 0.56

n = 10

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Originally posted by Fat Lady
(n+12) / (n+40) = 0.44

n + 12 = 0.44 * (n + 40)

n + 12 = 0.44n + 0.44*40

n(1 - 0.44) = 0.44*40 - 12

n = (0.44*40 - 12) / (1 - 0.44)

n = 5.6 / 0.56

n = 10
correct

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Originally posted by GinoJ
A player has 12 hits after 40 times a bat. How many additional consecutive times must the player hit the ball to achieve a batting avarage of 0.440?

Show your solution.
I don't know much about baseball (and even less about "eeze baseball", whatever that may be), but let's assume that you want the number of hits divided by the number of goes to be 0.440
So (12+x)/(40+x) = 0.440
where x is the number of extra goes.
Solving for x gives 10.

Is this what you were after?

[edit: OK - in the time it took me to type this the question was answered!]

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Originally posted by GinoJ
correct
at least you managed that without any edits ๐Ÿ˜›

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Originally posted by aging blitzer
at least you managed that without any edits ๐Ÿ˜›
The "reply and quote" button preserves their original comments for posterity, before they can edit them.

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Originally posted by GinoJ
correct
I just went, 12+10, 40+10, 22 out of 50, didn't need any math. First guess did it.

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Originally posted by sonhouse
I just went, 12+10, 40+10, 22 out of 50, didn't need any math. First guess did it.
Yes!

Even better.

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Originally posted by GinoJ
Yes!

Even better.
How is a guess better than solving it logically?

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Here's another baseball question...no math involved...

If a player hits a ball which spins backwards, then forwards, then hits the pitcher's mound, then bounces into the other team's dugout, what does the umpire call?

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Originally posted by wittywonka
Here's another baseball question...no math involved...

If a player hits a ball which spins backwards, then forwards, then hits the pitcher's mound, then bounces into the other team's dugout, what does the umpire call?
Foul ball, assuming no one touched it while it was in fair territory. Even though the ball hit the mound, which is in fair territory, it bounced into foul ground (the dugout) before passing first or third base. When you say "spins backwards," I assume you mean while in the air. If it spins on the ground behind home plate, it is foul no matter what happens after that.

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Originally posted by XanthosNZ
How is a guess better than solving it logically?
Nobody asked your opinion on this issue.

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Originally posted by GinoJ
Nobody asked your opinion on this issue.
Notice how I didn't give an opinion I asked a question.

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