09 May '08 21:56>
Originally posted by SwissGambitOk, let's analyze cases where the promoted piece is still on the board in item #5.
5...a1R 6...Rxc1 7...Rxd1+ 8.Kxd1 12.Kb3 Qa1 13...Qxf1 14...Qa1 15...Qa5 16.Ra1 Ba3 17.Ka2 21.Ke1 Qxa1# - the sequence is fast enough.
Black's moves: 7 for Pa7, 7 for Qd8, 3 for Bd4, 5 for other pieces = 22 total moves. Bust!
Edit: I crossed Item #5 off the list too soon. I cannot just assume the promoted piece that takes c1 gets captured. Maybe it's still on the board. More next post....
A promoted Q remaining on board is obviously slower than the previous sequence [she still has to clear the a-file after taking c1 AND the other Q has to come in].
With promoted R:
5...a1R 6...Rxc1 7...Ra1 8...R1a6 9.Qa1 Rah6 14.Kb3 Qxa1 15...Qxf1 16...Qa1 17...Qa5 18...Ba3 19.Ka2 23.Ke1 - abysmally slow.
With promote N:
5...a1N 7...Nxc1 8...N~ 9.Qa1 14.Kb3 Qxa1 turns out just like the promoted R scheme.
NOW we can cross Item #5 off the list.