1. Joined
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    25 Aug '06 13:55
    Originally posted by Agerg
    Its 30 degs
    I'm almost certain you're wrong about that. Do you want to provide any evidence?
  2. Standard memberAgerg
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    25 Aug '06 14:00
    read about 3 posts upwards from the one i posted 🙂
  3. Joined
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    25 Aug '06 14:57
    I think I've got a proof that angle BDE = 20 degrees. I'll try throwing some diagrams together in Paint Shop Pro. It uses properties of isosceles trapeziums, which may cause some confusion as it seems that Americans call trapeziums trapezoids, and conversely call trapezoids trapeziums!
  4. Standard memberThe Plumber
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    25 Aug '06 19:482 edits
    Originally posted by Agerg
    Its 30 degs
    That is correct.
  5. Standard memberAgerg
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    26 Aug '06 12:01
    I've tried to prove it cleanly by angle wrangling, but I'm getting bogged down trying to simplify a bazillion trig expressions and making silly errors..At some point I have to use the angle bisector theorem or the cosine rule...both of which yield ugly expressions that have only worked so far with my calculator... There must be a simple and elegant proof but I'm still searching for it 😳
  6. Joined
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    26 Aug '06 21:241 edit
    Ok, you're right, it's 30 degrees. Here is my solution. which I think is resonably elegant.

    1) Add another point, F, between D and C such than angle CBF = 20 degrees.

    2) Angles in triangle BCF add up to 180, so BFC = 80.

    3) Hence triangle BCF is isosceles, with BC = BF.

    4) Angles in triangle BEC add up to 180, so BEC = 50.

    5) Hence triangle BEC is isosceles, with BE = BC.

    6) So BC = BF = BE.

    7) Angle FBE is 80 - 20 = 60.

    8) Hence triangle FBE has two equal sides and one angle is 60, thus it is equalateral.

    9) Hence EF = BF (= BC = BE)

    10) Angles in triangle BDC add up to 180, so angle BDC = 40.

    11) Angle DBF also equals 40.

    12) Hence triangle FBD is isosceles, with BF = DF.

    13) So we have DF = EF

    14) Hence triangle FED is isosceles, with EDF = FED = (180 - 40) / 2 = 70.

    15) Hence BDE = 70 - BDC = 70 - 40 = 30.
  7. Joined
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    26 Aug '06 23:412 edits
    Originally posted by Agerg
    I've tried to prove it cleanly by angle wrangling, but I'm getting bogged down trying to simplify a bazillion trig expressions and making silly errors..
    😵

    http://mathcircle.berkeley.edu/BMC4/Handouts/geoprob.pdf
  8. Standard memberAgerg
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    28 Aug '06 17:541 edit
    Fat Lady...good work! (beats the hell out of mine)🙂
  9. Joined
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    13 Oct '06 05:36
    would it be stupid to say 310 degrees?

    if so then i'll go for 50 degrees, one or'tuvva.

    I dunno, i should go to sleep.
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