Five 0s

Originally posted by Suzianne
ack, tried to make it a link but dunno the bracket code for it

I'll teach you what it is then . 0! =
That is blank because theoreticlly , you are using one number multiplying by a number that does not exist but I think Mr. Calculus should know why it is , its like 4p4 = 4! / 0!
You already know that "p" means to "permutate" , so you know that
npr where n and r are random numbers ,
npr = n! / n-r!
Therefore , 4p4 = 4! / 0!
= 24 / 0!

Full Info. on Permutation
npr is a number .
It is more difficult to simplify it to one number than be able to do something a "normal human" would not be able to do .
First , we know by theory , npr = (n!) / (n-r)!
Next , what is n! ? It is n (n-1) (n-2) (n-3) ... (n-r+1) (n-r) (n-r-1) ...
3 x 2 x 1 so basiclly , its multiplying a number from itself down to 1.
Point is now , that 0 is below 1 , so 1 is the least you can get out of it , I'm not sure what to do with negative integars but 0! is defeinately 1 .

Originally posted by Coconut
Thread ID links aren't possible and neither are URLs yet.

Originally posted by Coconut
0! is one? That's a new one for me.

The factorial of negative numbers will defenately be a strange and medicore number . It may be either of these :
The Number itself
0
1
-1
Infinite
i
or some really wierd number.

you can not take the factorial of a negative number. They are undefined.

Originally posted by GWUchessmaster
you can not take the factorial of a negative number. They are undefined.

Originally posted by rheymans
He was probably talking about the Gamma function. Gamma(X) = (X - 1)! if X is an integer. The Gamma function is defined for some negatives. It is also defined for all positive Reals.