Genetics puzzle

Originally posted by hankthebeast
we have 26 pairs of chromosomes, so we would have had to get exactly the same set of chromosomes from each parent. The likely hood of getting the exact same set from the father is 1/(2^26), the likelyhood of getting the same set from the mother is also 1/(2^26). Do we then just add the exponents? If so it would hem be 1/(2^52). I'm not sure if that's right. We could also have to use the combinatorial equation.

23 pairs of chromosomes not 26 - but yeah the logic is good to that point so we have 1/(2^46) the problem is now working out the probabilty of crossovers in each chromsome....... I cant find detailed info regarding the average per chromosome and exact locations etc and the crossover locations are not entirely random plus there's interference........

1/(2^46) is large enough though.