Originally posted by Ramned
1-2: What is the apothem of a regular heptagon with a side of 10 and an area that is equal to the area of a hexagon? -- The regular hexagon has a side of 12. ([b]tough?)
3-4. What is needed to find the volume of a pyramid, slant height or height? What about a cone?
5. What is the formula you use to find the area of a rhombus?[/b]
1-2. well...area = apothem times perimeter divided by 2. so...
Area of this hexagon would be... (6) 1/2 * b * h of one triangle derived from a hexagon being 6 equplateral traingles emanating from one center point.
area of the hexagon is 374.12.
side of hept = 10 * 7 sides = 70 total units = P
AP/2 = Area = Area of hex.
AP/2 = 374.12
A(70)/2 = 374.12
35A = 374.12
Apothem = 374.12/35 = 10.6892278
(not tough at all)
3-4. To find the volume of a pyramid you need height from base to apex and area of the base. Slant height is used in finding surface area of a pyramid.
In a cone you need radius (to find the area of the base) and height.
5. area of a rhombus is bh. (base * height)