Originally posted by Codfish
How many non-intersecting chords of length N can fit into a circle of radius R?
P.S. If you don't know what this means, don't even try.
P.P.S. Show your work or you'll get no credit
At first glance I would say the answer is the following:
1, if N = 2R.
The nearest whole number that is less than or equal to Pi/[InverseSine(N/2R)], if N < 2R.
Is this what you got?
Edit: To get the above answer, I am simply dividing 2*Pi by the angle ACB, where A and B are the terminal points of some chord of length N, and C is the center of the circle.