You win the game if
* you get score n. Everyone else has to try to get to n+1, they try and fail.
* what if you fail? Do you automatically lose so in a two-player game player 2 just looks at your failed coin toss and says "I win" without tossing the coin? Or do you still win if everyone else fails too
(as you got zero pts first)? Will the others go for a win (possibly multiple rolls if there are 3+ players) or just try to defeat you (if you fail, everyone else rolls only once) ?
A Russian roulette variant of that.. you accept n chances of one in six of dying, all your opponents have to face the odds n+1 times; of an opponent survives n+1 clicks he'll use the gun on you and you lose. I find three clicks to be optimal vs one opponent (29% chance of win), five against two opponents 17% chance), seven vs three (12% chance), 8 vs 4, 9 vs 5, 10 vs six or seven, 11 vs six, 12 vs seven or eight, and 13 vs nine or ten, at which point survival chances are a humble 3%.