Eight years ago, Mary was half as old as Jane will be, when Jane is one year older than Tim will be at the time when Mary will be fice times as old as Time will be two years from now.

Ten years from now, Tim will be twice as old as Jane was when Mary was nine times as old as Tim.

When Tim was one year old, Mary was three years older than Tim will be when Jane is three times as old as Mary was six years before the time when Jane was half as old as Tim will be when Mary will be ten years older than Mary was when Jane was one third as old as Tim will be when Mary weill be three times as old as she was when Jane was born.

Mary is three times as old as Tim will be in 2 years. Jane is a little more than half Mary's age, and in forty years will be eight times as old as Tim is in three.

Originally posted by WeakSoss Eight years ago, Mary was half as old as Jane will be, when Jane is one year older than Tim will be at the time when Mary will be fice times as old as Time will be two years from now.

Ten years from now, Tim will be twice as old as Jane was when Mary was nine times as old as Tim.

When Tim was one year old, Mary was three years older than Tim will be w ...[text shortened]... e when Mary weill be three times as old as she was when Jane was born.

How old are they now??

Mary is 15, Jane is 8 and Tim is only 3 years old.

Originally posted by Bowmann Simple. In fifteen years they'll be 10.

I wonder how many candles there were on the bday cake in the first few years after that person's birth. Maybe some antimatter candles?

Anonther interesting aspect of this is, that if you make puzzles where the different ages are expressed by roots and pulling roots of negativ ages will leave you with a real and/or complex part of the persons age. can you come up with one bowmann? ðŸ˜›