- 02 Jun '07 12:05I was pushing a bottle cap around and I thought of a problem that I wasn't able to solve..... here it is

You have a wheel... with a radius (X), attached by an axle you have another wheel with radius (Y) pushing this wheel around it will eventually complete a circle with the radius (R)

Now,.. the ratio (X:Y) must be directly related to (R) I'm having trouble logically working through this. - 02 Jun '07 12:10By the sounds of things, you want like a wonky half of a car? In which case x and y have no baring on r. If you have a 3cm wheel attached by a short bar to a 10m wheel, it will make a small circle. If you have a 3cm wheel attached by a very long bar to a 10m wheel, it will make a large circle.
- 02 Jun '07 12:30

I don't understand...... you said x and y have no bearing on r, but then you stated that variable wheel sizes will change (R) if X and Y vary then it does directly affect (R)*Originally posted by doodinthemood***By the sounds of things, you want like a wonky half of a car? In which case x and y have no baring on r. If you have a 3cm wheel attached by a short bar to a 10m wheel, it will make a small circle. If you have a 3cm wheel attached by a very long bar to a 10m wheel, it will make a large circle.** - 02 Jun '07 12:42

wait you said bar lenghts sorry......... You might have missunderstood me..... If the whel size only slightly varies, the resulting path will be a circle with a greater dia. if they vary a great deal the resulting dia. will be much smaller*Originally posted by joe shmo***I don't understand...... you said x and y have no bearing on r, but then you stated that variable wheel sizes will change (R) if X and Y vary then it does directly affect (R)** - 02 Jun '07 12:47Radius X is the radius of the base of a cone, The radius 'R' of the circle made by the two wheel combination is equal to the hypotenuse of the the cone...

X = radius of base of cone

R = hypotenuse of cone...

H = height of cone

Pythagoras's rule gives you each of these values but your question was about how the length of the axle affects the length of the radius of the turning circle.

Well, the wheel 'Y' and the axle have a relationship, if one stays constant, but the other increases the size of R increases, because the second wheel 'Y' is effectively a cross section of the cone. - 02 Jun '07 13:00

can you solve this for me ? This should be my question*Originally posted by agryson***Radius X is the radius of the base of a cone, The radius 'R' of the circle made by the two wheel combination is equal to the hypotenuse of the the cone...**

X = radius of base of cone

R = hypotenuse of cone...

H = height of cone

Pythagoras's rule gives you each of these values but your question was about how the length of the axle affects the length of the ...[text shortened]... of R increases, because the second wheel 'Y' is effectively a cross section of the cone.

You have one wheel with a radius of 4" and another wheel with a radius of 2" connected by an axle... if you give them a push from point (A) what will be the dia or radius of the outermost circle when the wheels cross point (A) again?