1. Joined
    08 Jul '02
    Moves
    150831
    03 Oct '02 22:07
    I'll get that blasted Road Runner yet! Argggh!

    Coyote
  2. Standard memberSchliemann
    The Diplomat
    Slightly Left :D
    Joined
    22 Jun '01
    Moves
    8518
    29 Sep '02 02:22
    No...it just takes away from all of the things I have to
    say...hehehe..just kidding...I like the logic problems but they do need
    their own deal...remember this is a communitity and Russ and Chris
    are doing everything they can to make this the best site on the web!

    And doing a hell of a job of it too!!

    Dave
    Proud Pawn Star
  3. Standard memberBarefootChessPlayer
    Barefoot Chessplayer
    central usa
    Joined
    22 Jul '03
    Moves
    61025
    19 Nov '03 18:00
    it can't be done, because, as has been shown, your speed would have to be such that you could cover the distance in zero time!
    if you come back at 120, your return-trip time would be 1/4 of your out-trip time, but your _average_ is only 48 mph!
    try 150. now your average speed is only fifty.
    it doesn't matter what the speeds involved are--there is no way you wil ever be able to average twice the speed on a return trip over the same distance!
  4. Standard memberTheMaster37
    Kupikupopo!
    Out of my mind
    Joined
    25 Oct '02
    Moves
    20443
    19 Nov '03 18:31
    Distance X. Time on the way there X/30. Average 60. Total distance 2X. Total time 2X/60 = X/30.

    Time for the way back X/30 - X/30 = 0
  5. Joined
    26 Apr '03
    Moves
    26771
    19 Nov '03 19:06
    Originally posted by Acolyte
    "Both distances are the same."

    Joke? If so, you can explain the flaw in this reasoning better than I am about to.

    If not, the flaw is that, taking 'average' to mean 'mean', average speed is the sum of each
    speed multiplied by the TIME spent at that speed, divided by total TIME. If instead we
    performed the calculation using DISTANCE instead ...[text shortened]... those can never be higher than
    30mph unless you take a detour. But that's another matter...
    To those who think the answer is 90 or 120:

    Say its 30 miles to work, I drive there at 30mph, it takes me 1 hr

    I drive back at:
    a) 90 mph, now its taken me 1 hr and 20 mins to go 60 miles
    b) 120 mph, now its taken me 1 hr and 15 mins to go 60 miles
    c) infinity mph, now its taken me 1 hr to go 60 miles (but I've used a lot of fuel)

    I think only c is an average speed of 60 miles per hour.
  6. DonationChris
    Site Admin
    Wimbledon
    Joined
    21 Feb '01
    Moves
    26275
    20 Nov '03 12:492 edits
    Crikey - this thread, long time, no see.

    As I set this poser, I guess I should officially state that the answer, of course, is that it can't be done. As for whether it can be done at infinity MPH I don't know - I guess that this would be infinitely close to an average of 60mph, but would it be spot on? Too hard for my brain.

    It can't be done, because, as has been said many times already, if you want to average double the speed of your outward trip, you would have to return in no time at all, therefore travelling twice the distance in the same amount of time.

    -Chris
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