Originally posted by Ason Pigg2
i did a competition today and only one problem i couldn't figure out, it is hard hard hard hard hard, if you can help please do and give your answer and how you did it.
a triangle with lenths 8,10,12 has an angle bisecter that bisecs the angle formed by the 8 and 10 lines, 2 segments are formed on the lenth 12 line, find the lenth of the 2 segments.
Solve the angles of the triangle (it's case 2)
Then, as the one angle is bisected, you know the values of the two new angles will be half.
Now you have an ASA triangle, which is made up of the 8 (or 10, depending which you pick) and the two known angles. Solve this triangle. It's case 1 in the link above.
This should be in Pozers and Puzzles. I've alerted it, so it might get moved there.