Originally posted by blindcheesecake If on day 1 you got 1c then 2c on day 2 and 4c on day 3 and 16c on day 4 and so on, How much money would you have after 8 years 3 months and 12 days, if you were born on June 8 1124. Be shure to include leap years.
Originally posted by Gastel Actually, $112,350,873.35
If the series is what you say it is (Tn = 2^T(n-1)) then on day 5 you recieve 2^16 or 65536 cent and on day 6 you recieve 2^65536 cents which is horrible to contemplate.
Originally posted by XanthosNZ If the series is what you say it is (Tn = 2^T(n-1)) then on day 5 you recieve 2^16 or 65536 cent and on day 6 you recieve 2^65536 cents which is horrible to contemplate.
Actually 2^65536 doesn't exist. Everytime I enter into my calculator it just says #ERROR and Excel just says #NUM! (as it is very excited about this). So my conclusion is that the number doesn't exist, because for it to exist we must be able to see it.
How I got my answer was by another method though. I've PM'd Sicilian Smaug and he used a similar method, so I suggest our answers are correct or at least close. Although the thread starter seems to have disappeared so I think our hypothesis' are falling on deaf eyes (because he has to read it).
Originally posted by Gastel Actually 2^65536 doesn't exist. Everytime I enter into my calculator it just says #ERROR and Excel just says #NUM! (as it is very excited about this). So my conclusion is that the number doesn't exist, because for it to exist we must be able to see it.
How I got my answer was by another method though. I've PM'd Sicilian Smaug and he used a similar metho ...[text shortened]... isappeared so I think our hypothesis' are falling on deaf eyes (because he has to read it).
But if both Tn = 2^T(n-1) and some other rule (which you used to find your answer) both fit the sequence given in the starting post then it is underdefined.
Originally posted by Gastel Actually 2^65536 doesn't exist. ...for it to exist we must be able to see it.
It does exist: it's a 20020 digit number begining 200352993040684646497... and ending ...5587895905719156736. Obviously to large to type into this box, but if you want to see it (and believe it) you'll need to stop messing around with calculators and Excel, find yourself a Unix box and type in the following incantation: echo "2 65536 ^ p" | dc
Originally posted by howardbradley It does exist: it's a 20020 digit number begining 200352993040684646497... and ending ...5587895905719156736. Obviously to large to type into this box, but if you want to see it (and believe it) you'll need to stop messing around with calculators and Excel, find yourself a Unix box and type in the following incantation: echo "2 65536 ^ p" | dc
Calculators? Excel?? These calculations should be done with our human brains. Technology is causing us to lose the fundamentals!
Originally posted by blindcheesecake If on day 1 you got 1c then 2c on day 2 and 4c on day 3 and 16c on day 4 and so on, How much money would you have after 8 years 3 months and 12 days, if you were born on June 8 1124. Be shure to include leap years.
That amount would be !#@%$^#@$ can't find the word to say!!
If you got a penny every day...
30 May '06 20:25
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