Originally posted by ilywrin Is it just one piece that is placed? If, yes, I cannot find a solution 🙂
And one more thing the diagram is not turned around is it?
Yes, just one piece is placed.
However, it is necessary to read the stipulation quite literally to solve this.
Well as it is a 'trick' problem, that could make it either a knight or bishop on b6. Aside from Bxa7 or Bc5, any move should result in stalemate.
You cannot prevent the queen from moving, short of surrounding it. And a capture cannot be made by a rook or queen without giving check. It cannot be taken without a rook or queen on a8, as the pawn could then move.
The last king move would need to be from moving out of check by the rook (whites previous move being Rxb5+. So this means the white piece has to be a knight, a bishop would have prevented the king previously being on a5. Previous black moves prior to the final king move could come from several pieces.
Originally posted by Peakite Well as it is a 'trick' problem, that could make it either a knight or bishop on b6. Aside from Bxa7 or Bc5, any move should result in stalemate.
You cannot prevent the queen from moving, short of surrounding it. And a capture cannot be made by a rook or queen without giving check. It cannot be taken without a rook or queen on a8, as the pawn could then ...[text shortened]... or to the final king move could come from several pieces.
So, is this even possible?
-The black queen can't be prevented from moving on the next turn. If you pin it to the king with a rook/queen along row 6, the queen just takes whatever piece you're using.
-If you take the black queen, the only way to prevent PxB6 is to place a rook/queen at A8. But, if you do that, the only way to take the queen is RxB6, which is checkmate, not stalemate.
Unless....a "careful reading" of the OP states "Place any piece on any empty square". If that includes moving one of the pieces already on the board, then move the Black Queen to D7, and QxD7 is stalemate.