- 17 Jun '04 01:32

Cool! I think you're right bbarr, the answer is zero for the reason you stated. And I was going to add that THUDandBLUNDER should have stated that only one letter should go into any one envelope, but that would given to big a clue to the solution and made it too easy.*Originally posted by bbarr***Tricky. The probability is 0. If three are correct then the fourth must be also. Of course, the probability I gave above was for randomly placing all four envelopes correctly.** - 18 Jun '04 08:19 / 1 edit

Perhaps I should have made it clear that one and only one letter goes into each envelope, in which case the right answer is zero.*Originally posted by Otis***what if i stuffed 3 letters in the correct envelopes and then stuffed the extra letter with another letter leaving an envelop empty then there could be 3 correct and 1 false**

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