12 Feb 06
Two boys and a girl were hiding in a tree house during a heatwave. One of the boys had three bottles of lemonade with him and the other had five. They shared the the eight bottles of lemonade equally between the three of them. When they came down from the tree house, the girl gave the boys eight sweets as payment. What is the fairest method of dividing the eight sweets between the two boys?
12 Feb 06
Originally posted by derts2.6666667 to the first and 5 to the second.. and the rest? well, she can have..
Two boys and a girl were hiding in a tree house during a heatwave. One of the boys had three bottles of lemonade with him and the other had five. They shared the the eight bottles of lemonade equally between the three of them. When they came down from the tree house, the girl gave the boys eight sweets as payment. What is the fairest method of dividing the eight sweets between the two boys?
12 Feb 06
Originally posted by celticcountryClearly not, since the boys didn't give an equal amount of drinks to the girl.
4 each.
next teaser.
Boy 1 had 3 bottles, equal to 9/3
Boy 2 had 5 bottles, equal to 15/3
Total of 8 bottles.
Each person has 8/3 bottle of drinks to consume.
Boy 1 gave off 1/3
Boy 2 gave off 7/3
In order to be as fair as possible, the girl would give 1 sweet to Boy 1 and 7 sweets to Boy 2.
You disappoint me Celtic.