Originally posted by idioms
Yep that's right, the formula you gave is the lower bound of this problem. What if the highest rating of my opponents was also 1800? would the formula still be valid?
There certainly are lots of combinations but the number is finite as your opponents rating has an upper bound of 2455
For the different combinations, I guess you'd have 2455-1357+400 different ratings possible for your first game, then 2455-1357+400-32 different ratings for your second, so that's
1498+32n possibilities for each game where n will run from 0 to 13 (For each of the 14 games).
So multiply them together to get the permatations.
(1498-32*0) * (1498-32*1) * (1498-32*2) * .... * (1498-32*13)
I could calculate a figure at this point, but there must be a better way to express this mathematically, it's been too long since I've done this kind of stuff, my memory fails me right now!