Go back
Minimize function

Minimize function

Posers and Puzzles

Vote Up
Vote Down

Originally posted by ark13
From these results, we can assume that the positive minimizing value of x in x^x^x^x is 1/cubrt (e), and etc. Almost makes you wonder why names of operations stop at exponents. Why isn't there an operation that is the number of times a number is put to it's own power? Well, I guess they had to stop somewhere.
Yes, your answer to your latest question is correct. Have you taken Calc II yet? That's where you learn log differentiation. With that as a tool, getting the solution to mins and maxes of simple exponentials is not difficult. If you are interested, I can tell you how it is done.

Vote Up
Vote Down

Originally posted by rheymans
Yes, your answer to your latest question is correct. Have you taken Calc II yet? That's where you learn log differentiation. With that as a tool, getting the solution to mins and maxes of simple exponentials is not difficult. If you are interested, I can tell you how it is done.
Nope, no calc at all. That's why I needed assitance for these.

I certainly wouldn't mind learning the simple method. You could PM me.