Originally posted by iamatiger
While the fan is spinning fast but the circuit is cut, does the motor build up a charge because the fan is trying to push electrons through the circuit? Then when the fan stops, this charge can finally dissipate which gives a small current flow, turning the fan a bit the other way?
The reason Coquette says no is when the motor is turned off, it loses the ability to conduct electrons in the normal way, through completed circuits.
In that condition, there would be an electron charge and a short time of some of that charge going to ground through capacitance discharge of the motor windings but after that there would be just a small voltage built up as long as the motor is turning.
The problem for EMF to cause the reversal is such charges would be long gone when the blades are turning a couple of RPM and slowing down. The electron movement generated by the turning blades would be all dressed up and nowhere to go.
As an example, suppose we have an ordinary extension cord, say 100 feet long, just the double wire, with insulation of course. Both ends are not connected to anything. Then connect a battery to the two wires at one end.
For a brief moment, electrons will flow from the battery down the wire and at the speed of about 10 nanoseconds per foot, so about 1000 nanoseconds later (electrons in copper moves only about 10% of the speed of light, which is about 1 nanosecond per foot) said electrons meet the other end of the wire and find nowhere else to go.
In that 1000 nanoseconds of time, because there is a voltage gradient along the wire, there will be some transfer of charge across the insulation due to capacitance effects.
However, after the electrons have proven to themselves there can be no further movement or transfer across the insulating barrier, all electron movement stops and thereafter only maintains the DC charge of whatever voltage the battery has provided. Of course, if you short out the wires at the other end of the cable, electrons will move bigtime and you will have a massive current in the wire, depending on the internal resistance of the battery.
For instance, if it was a watch battery, there would be a rather high internal resistance and not much current could flow, limited by the small chemical charge available in that little button cell.
If it was a fully charged automobile battery, shortly after you established the connection at the long end of the cable, it would in short order start heating up and most likely start melting and burning the insulation because the internal resistance is very low in auto batteries and the chemical charge very large, thousands of watts available for a few minutes, more than enough to burn up the cable.
None of that can happen when the far end of the cable is disconnected, and it doesn't matter at that point if the battery is a button cell for a watch or a thousand auto batteries in parallel, the current flow across the insulating barrier through capacitance is only in proportion to the voltage of the battery and the distance between the wires and the type of insulation between the wires.
That capacitive current only lasts for nanoseconds or microseconds at best so in the fan motor, there would be not enough energy to start anything going in either direction. The blades of a regular ceiling fan are rather massive and it takes a fair amount of energy to cause some initial movement, which you can verify for yourself by just turning the blades by hand, you can feel the resistance to motion due to the blades mass. Way too heavy for transient effects of capacitive discharge to make any headway to move said blades.