Originally posted by sonhouseIf the pendulum is perfectly along the equator, the Coriolis acceleration would be zero, I think. It sounds weird but it would be a line.
In the middle of Foucault's Pendulum, Umbertro Eco and wondered what the shape of the circle it covers, at the N & S poles, presumably it would describe a perfect circle but what about at the equator? Would the shape still be a circle or would it be an ellipse? Or just a straight line. Can't see it being a straight line, I would think that would only happen if the planet under it was not rotating.
Originally posted by XanthosNZI didn't understand the effect caused by the fixed stars. Would the pendulum be in a straight line or not?
I had to think long and hard about this problem. Actually no I didn't I just looked up the wikipedia page and there are the answers.
Originally posted by FabianFnasWhat are you defining as the 'wavelength'? The size of the circle it proscribes?
As I see it the answer would be something like this:
If the pendulums first wavelength is a stright line it will still be a straight line in the following wavelength, disregarding the position of the earth.
The same thing happens also if the first wavelength is a perfect circle or a ellips.
It just continues as it is started.
Originally posted by naryaIndeed. There are so many referances its like an occult Finnegans Wake. I am about in the middle so have yet to finish it. Am very busy right now, emails to write, music files to send, all not done yet, have to pick up my honda tomorrow, bad transmission shift cable, it seems like an endless list of things to do before I get back to it.
Great book, by the way. Much better than DaVinci Code.