PG in 21.0

Originally posted by Tetsujin
It works easily if black doesn't even start with a bishop.

Perhaps, the player just took it off the board, or they agreed to the handicap?

This isn't a trick problem; there is a single (difficult) solution to be found.

Originally posted by Peakite



White moves 6P, 5K, 2B leaving 8 for the rook.
So it can go from h1 to h4/h5 (not sure which but leaning towards h5), then to a4/a5, a8 and f8 before returning. Which is all of his accounted for.

So black has a minimum of three pawn moves (to b4 and a5), the rest to shuttle his pieces out and back again. So max of 18 to do this, or 9 each way. K mi ...[text shortened]... can't take place before the 5th move. K to c3, pawns to e3/b3. a5, b5, Nc6 and Rb8 needed first

Well the king may come through e2-d3-c4-b3-a2, after Whiite has moved the a pawn to a3 and before moving the b pawn. Maybe. I don't have time to look at it more carefully now.

With that I'm down to 22 moves now:

1. h4 a5
2. h5 Nc6
3. h6 Rb8
4. Rh5 b5
5. e3 b4
6. Rxa5 Rb5
7. Ra8 Ba6
8. Ke2 Qb8
9. Kd3 Kd8
10. Kc4 Kc8
11. Kb3 Kb7
12. a3 Qa7
13. Rxf8 Rb6
14. Ra8 Qb8
15. Ka2 Kc8
16. b3 Kd8
17. Bb2 Ke8
18. Bf6 Qd8
19. Ra7 Bc8
20. Ra5 Rb8
21. Rh5 Ra8
22. Rh1 Nb8

Got it.

PMing a solution

Peakite has solved this problem.

Only peakite got the solution.

1.h4 a5 2.h5 Ra6 3.h6 Re6 4.Rh5 Nc6 5.Rxa5 b5 6.Ra8 Ba6 7.e3 Qb8 8.Ke2 Kd8 9.Kd3 Kc8 10.Kc3 Kb7 11.Kb3 Qa7 12.Rxf8 b4 13.Ra8 Qb8 14.a3 Kc8 15.Ka2 Kd8 16.b3 Ke8 17.Bb2 Qd8 18.Bf6 Bc8 19.Ra5 Nb8 20.Rh5 Ra6 21.Rh1 Ra8