Originally posted by st dominics preview
if I have understood the problem, I reckon on the 84th day there will be 82 whole pills and 84 half pills (the day before, the 83rd, there would be 84 whole and 83 halves)
IF I have understood the problem!
You got it. Count halves H up by one per day D and wholes W down by two per day D, and see when the difference is minimized. This is brute force.
one any day, after dosing, H=D, W=250-2D
The .33... means there is no day on which W=H.