1. Joined
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    09 May '07 18:39
    show steps
  2. Joined
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    09 May '07 21:09
    wow, i know its "tuf" by not that bad...
  3. Standard memberAThousandYoung
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    09 May '07 21:13
    1 = 1
    1 = (chair/chair)


    chair =/= (chair/chair)
    chair =/= 1

    OR

    1 = 1
    1 ton = wonton
    weight = soup
    scale = bowl

    Ummm...ok I'm stuck. Use the first proof.
  4. Joined
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    09 May '07 21:29
    Originally posted by AThousandYoung
    1 = 1
    1 = (chair/chair)


    chair =/= (chair/chair)
    chair =/= 1

    OR

    1 = 1
    1 ton = wonton
    weight = soup
    scale = bowl

    Ummm...ok I'm stuck. Use the first proof.
    getting very close ๐Ÿ˜€
  5. Account suspended
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    09 May '07 21:30
    Originally posted by AThousandYoung
    1 = 1
    1 = (chair/chair)


    chair =/= (chair/chair)
    chair =/= 1

    OR

    1 = 1
    1 ton = wonton
    weight = soup
    scale = bowl

    Ummm...ok I'm stuck. Use the first proof.
    chair could equal chair/chair if under the domain chair = one
  6. Standard memberAThousandYoung
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    09 May '07 21:33
    Originally posted by rubberjaw30
    chair could equal chair/chair if under the domain chair = one
    Huh? I've never heard a domain described as an equation. Domain is what you plug into a function and you get the range. I'm confused.

    In any case, aren't we trying to prove that chair does NOT equal one? Unless you're using a trick where one does not equal 1, which could be clever.
  7. Account suspended
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    09 May '07 21:38
    Originally posted by AThousandYoung
    Huh? I've never heard a domain described as an equation. Domain is what you plug into a function and you get the range. I'm confused.

    In any case, aren't we trying to prove that chair does NOT equal one? Unless you're using a trick where one does not equal 1, which could be clever.
    i mean that it could work if chair and one are equal, meaning that that guy's proof is invalid
    the proof that chair and one are not equal is not valid if the proof is disproven by saying that 1 = chair
  8. Standard memberAThousandYoung
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    09 May '07 21:472 edits
    Originally posted by rubberjaw30
    i mean that it could work if chair and one are equal, meaning that that guy's proof is invalid
    the proof that chair and one are not equal is not valid if the proof is disproven by saying that 1 = chair
    If 1 = chair, then this puzzle is impossible to solve..."who gave you permission" to assume that 1 = chair? Where did you get that from?

    EDIT - I think I get your point, despite your very poor attempt at getting it across. Are you saying I cannot assume chair =/= chair/chair because I haven't yet proved that chair =/= 1?

    By the way, I am "that guy".
  9. Account suspended
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    09 May '07 21:54
    Originally posted by AThousandYoung
    If 1 = chair, then this puzzle is impossible to solve..."who gave you permission" to assume that 1 = chair? Where did you get that from?

    EDIT - I think I get your point, despite your very poor attempt at getting it across. Are you saying I cannot assume chair =/= chair/chair because I haven't yet proved that chair =/= 1?

    By the way, I am "that guy".
    only by assuming that something is true, and then finding where it contradicts fact, can it be disproven...
    for example...
    1=2we assume this is true until we discover that this means that one would have to equal one more than itself, which we know is false...
    that's an extremely sinmple example, but you get the idea...
  10. Account suspended
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    09 May '07 21:55
    Originally posted by AThousandYoung
    If 1 = chair, then this puzzle is impossible to solve..."who gave you permission" to assume that 1 = chair? Where did you get that from?

    EDIT - I think I get your point, despite your very poor attempt at getting it across. Are you saying I cannot assume chair =/= chair/chair because I haven't yet proved that chair =/= 1?

    By the way, I am "that guy".
    your edit is correct, forget my last post then
  11. Joined
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    10 May '07 01:37
    keep it up, your almost to where i got stumped at....
  12. Joined
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    10 May '07 05:27
    ok...it went cold.... i did it 5 steps.
  13. Joined
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    10 May '07 05:29
    frog - = tadpool


    there is a middle step
  14. In Christ
    Joined
    30 Apr '07
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    10 May '07 05:57
    Here goes:

    c = 299,792,458 m/s (speed of light)
    h = 6.62606896 × 10^-34 J·s (Planck's constant)
    a = 0.5291772108 × 10^-10 m (Bohr radius)
    i = (-1)^(1/2)
    r = 8.314 472 J/(molK) (gas constant)

    Therefore chair = 8.7400207226450635243266130035272 x 10^-53 i [(Jm)^2]/(molK) =/= 1
  15. Joined
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    10 May '07 16:03
    Originally posted by Jirakon
    Here goes:

    c = 299,792,458 m/s (speed of light)
    h = 6.62606896 × 10^-34 J·s (Planck's constant)
    a = 0.5291772108 × 10^-10 m (Bohr radius)
    i = (-1)^(1/2)
    r = 8.314 472 J/(molK) (gas constant)

    Therefore chair = 8.7400207226450635243266130035272 x 10^-53 i [(Jm)^2]/(molK) =/= 1
    wow, well done, i got the same answer this way.

    1=arm
    arm x force=stuff
    *
    *inapropriate lines๐Ÿ™
    *
    frog-time=tadpole
    (forgot what i made up here
    and here 2 days ago)
    sun %charlie murphy=random calculator number
    random calc. #=8.74002..........................
    chair doent equal 1

    chair = good

    {rugters womens baseketball team not available for comment}
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