Originally posted by penleyi think the next set would be 3,3,5 again. that is, 3, 4, 5 in circular order. two 3s, one less which is 5; two 4s, one less; two 5s, one less; and since 3 follows 5, we are back to two 3s, one less, and so forth.
Try this: 3. 3, 5, 4, 4, 3, 5, 5, 4, ...
here is another really obscure one:
1, 7, 4, 2, 3, 5, 0, 6, 9, 8.