09 Jan '10 15:39

Would we be able of seeing through a sphere where for every point (x,y,z) , x,y,z are rational numbers?

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Out of my mind09 Jan '10 18:32

I don't think so. There might be infinitely many sight-lines but all of them are too small to let any photons through. I don't have the proof, but it results in something like this;*Originally posted by smaia***Would we be able of seeing through a sphere where for every point (x,y,z) , x,y,z are rational numbers?**

In*every*part of the sphere there are infinitely many rational points. So a photon would always hit infinitely many points on the sphere.- Joined
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09 Jan '10 21:34

That's precisely the case.*Originally posted by Palynka***I think what smaia is getting at is more related to the continuity of a sphere (i.e. is the mesh fine enough). Like wondering if the rational numbers are not complete, for example (which they are not).**

If that is the question, then the answer should be "no" as a sphere is a compact.

All that needs to be done is to prove such "sphere" is compact.- Joined
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Out of my mind10 Jan '10 10:35

The term I was thinking of was 'dense'.*Originally posted by smaia***That's precisely the case.**

All that needs to be done is to prove such "sphere" is compact.

"A space is compact", crudely said; "you can cover your space with finitely many 'tiles' of given size."

"A subset is dense", equally crudely said; "you can approximate every point in your space arbritarily well with points of the subset."

That you can cover the rational sphere with finitely many tiles of given size doesn't imply that you don't leave a hole somewhere. I think you need that the rational sphere is dense to be able to say that.- Joined
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at home10 Jan '10 11:04

Consider the sphere created by all the points (x,y,z)*Originally posted by smaia***Would we be able of seeing through a sphere where for every point (x,y,z) , x,y,z are rational numbers?**

such that x^2 + y^2 + z^2 < 1

and x,y and z are rational

(ie a sphere of radius 1)

If we we only consider points (Ap, Bp, Cp) where A,B,C are integers and p is half the size of a photon then we would have a mesh too fine to see through.

If however we assume the OP used 'see' to indicate the possibility of a 'line of sight' through the sphere then there are an infinite number of such lines of sight e.g any line on the plane x=pi/4- Joined
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Halfway10 Jan '10 13:401 edit

Oops, I don't know why I read real, where smaia wrote rational. ðŸ˜•*Originally posted by Palynka***I think what smaia is getting at is more related to the continuity of a sphere (i.e. is the mesh fine enough). Like wondering if the rational numbers are not complete, for example (which they are not).**

If that is the question, then the answer should be "no" as a sphere is a compact.

As wolfgang says, then the answer is yes and there are many such lines of sight as the sphere will not be locally compact.- Joined
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Halfway10 Jan '10 13:491 edit

In topology, dense sets are subspaces of a topological space and so are said to be dense*Originally posted by TheMaster37***The term I was thinking of was 'dense'.**

"A space is compact", crudely said; "you can cover your space with finitely many 'tiles' of given size."

"A subset is dense", equally crudely said; "you can approximate every point in your space arbritarily well with points of the subset."

That you can cover the rational sphere with finitely many tiles of ewhere. I think you need that the rational sphere is dense to be able to say that.*in*that space. It's a characteristic of subsets, not spaces. In that sense, the rationals are actually a dense subset of the real numbers!

However, the space generated by a real sphere with a point removed will not be a compact because you can construct a sequence of points within that space that in the limit approaches the removed point (outside the space).- Joined
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10 Jan '10 16:56

Can I throw a spanner in the works? It seems likely to me that firing a light source at this object would lead to scattering, using the wave-like behaviour of light. Thinking in terms of single protons probably doesn't work.*Originally posted by TheMaster37***There might be infinitely many sight-lines but all of them are too small to let any photons through.**

Not that I feel like trying to calculate the scattering pattern ðŸ™‚.- Joined
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10 Jan '10 18:42

I think there is a caveat - It is believed, but not yet proved, in nature, the distance between two points cannot be smaller than the planck lenght-> 10^^-32 meter. In this case, any finite length taken in the sphere has to be multiple of the planck length (Assuming the conjecture is correct). What happens then if a single photon hits the sphere?*Originally posted by mtthw***Can I throw a spanner in the works? It seems likely to me that firing a light source at this object would lead to scattering, using the wave-like behaviour of light. Thinking in terms of single protons probably doesn't work.**

Not that I feel like trying to calculate the scattering pattern ðŸ™‚.

Some commenters mentioned the "size"of the photon. What is the size of a photon? Assume the conjectiure is false and nature allows any distance to be as small as you want. Then the question is: what is the minimum distance that allows a photon to pass through?- Joined
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at home10 Jan '10 20:12

Yes ... you have caught me out!*Originally posted by smaia***I think there is a caveat - It is believed, but not yet proved, in nature, the distance between two points cannot be smaller than the planck lenght-> 10^^-32 meter. In this case, any finite length taken in the sphere has to be multiple of the planck length (Assuming the conjecture is correct). What happens then if a single photon hits the sphere?**

Some commen ...[text shortened]... want. Then the question is: what is the minimum distance that allows a photon to pass through?

What is the size of a photon?

I assumed that the question was a mathematical one, even though I gave two answers! (A 'reality' one and a mathematical one)- Joined
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