Originally posted by talzamir
Joe wrote: Can you walk me through the two pair calculation? I'm struggling to come up with it.
Actually.. I got annoyed at the mistakes I did in the first calculation, so I did it the easy way, and wrote a bit of code that went over the 7,776 combinations and checked what they are.
One pair is indeed in 3,600 combinations. In the first go I did it ...[text shortened]... ps are one of five, one of four, and one of three possibilities.
6 x 10 x 5 x 4 x 3 = 3,600.
Ok, I was asking how you calculated "two pair's" number of calculations, but don't worry about it. I did some research and found why I was twice as high, because in each one of the combinations the order of the pairs can be switched (e.g. 1,1,2,2,5 has a compliment combination where the order of the pairs are switched i.e. 2,2,1,1,5), I missed that entirely.