Please turn on javascript in your browser to play chess.
Posers and Puzzles

Posers and Puzzles

  1. 27 Aug '06 00:26
    If a rook and a bishop are placed on two randomly chosen squares of the board, what is the probability that either one of them will attack the other?
  2. 27 Aug '06 01:29 / 1 edit
    Originally posted by ThudanBlunder
    If a rook and a bishop are placed on two randomly chosen squares of the board, what is the probability that either one of them will attack the other?
    about 42.2% EDIT: never mind that doesn't work this one is tricky
  3. 27 Aug '06 18:21 / 2 edits
    Originally posted by ThudanBlunder
    If a rook and a bishop are placed on two randomly chosen squares of the board, what is the probability that either one of them will attack the other?
    Isn't it the probability that two queens attack each other? That can't be too hard to figure out...

    ...Edit: if you count placing them on the same square as "attacking each other" then it's

    (64 + 64*14 + B)/(64*64)

    where the B is the total number of squares a bishop can attack by placing it on all 64 squares of the chessboard. Starting from the middle four squares in the centre, and working outwards in concentric squares, we see

    B = 4*13 + 12*11 + 20*9 +28*7 = 560

    so the probability is 95/256. If you're not counting them being on the same square then take off the first 64 above to yield 91/256.
  4. 27 Aug '06 19:14
    Originally posted by SPMars
    Isn't it the probability that two queens attack each other? That can't be too hard to figure out...

    ...Edit: if you count placing them on the same square as "attacking each other" .
    Right idea, but no need for two queens.
  5. 27 Aug '06 20:03 / 2 edits
    Originally posted by ThudanBlunder
    Right idea, but no need for two queens.
    Yeah, it's just the way my thought process was going at the time...the problem looked simpler that way.
  6. 27 Aug '06 20:07 / 1 edit
    Rook attacking bishop: 14/63 (on any square where the rook is)
    Bishop attacking rook: (28 *7+20*9+12*11+4*13)/(64*63)

    Both are mutually exclusive. Sum: 36.11% (my guess).
  7. 27 Aug '06 21:30
    Originally posted by Mephisto2
    Both are mutually exclusive. Sum: 36.11% (my guess).