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Originally posted by orkyboythe same amount as the boat rises with the water as it is floating on it
when a boat is at anchor 5 of the rungs on the rope ladder over its side r underwater. if the rungs r 30cm apart r 3 inches thick how many rungs will be underwater in 4 hours time if the tide rises at 35cm per hour
Andrew
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Originally posted by orkyboyhere is another along the same lines....
when a boat is at anchor 5 of the rungs on the rope ladder over its side r underwater. if the rungs r 30cm apart r 3 inches thick how many rungs will be underwater in 4 hours time if the tide rises at 35cm per hour
"A ship loaded with iron ore is in a canal lock, with the gates closed at both ends. Suddenly the ship dumps its entire load of ore into the lock. Does the water level rise, stay the same, or drop?"
Andrew
Originally posted by latex bishopAssuming that the density of the ore is greater than that of the water, and that the ore is not shaped in such a way that it is able to float, I would have to guess that the water level relative to the canal lock would drop. When the ore is floating in the ship, it is displacing a volume of water X of equal weight to the ore. When it is submerged, the ore displaces a volume of water Y of equal volume to the ore. Since the ore is more dense than the water, X is larger than Y, and the submerged ore displaces less water. Less displaced water means lower water level in the lock. The water level relative to the ship should drop, too, since the ship is now carrying less weight and will bob up a bit.
"A ship loaded with iron ore is in a canal lock, with the gates closed at both ends. Suddenly the ship dumps its entire load of ore into the lock. Does the water level rise, stay the same, or drop?"
Andrew
- Joined
- 20 Feb 02
- Moves
- 58336
Originally posted by godzillionI do not know the correct answer, but I would go along with your logic
Assuming that the density of the ore is greater than that of the water, and that the ore is not shaped in such a way that it is able to float, I would have to guess that the water level relative to the canal lock would drop. When the ore is floating in the ship, it is displacing a volume of water X of equal weight to the ore. When it is submerged, the o ...[text shortened]... to the ship should drop, too, since the ship is now carrying less weight and will bob up a bit.
Andrew
Originally posted by godzillionSeems plausible
Assuming that the density of the ore is greater than that of the water, and that the ore is not shaped in such a way that it is able to float, I would have to guess that the water level relative to the canal lock would drop. When the ore is floating in the ship, it is displacing a volume of water X of equal weight to the ore. When it is submerged, the o ...[text shortened]... to the ship should drop, too, since the ship is now carrying less weight and will bob up a bit.