28 Sep '10 20:32>
Originally posted by ThomasterI can't believe that you and clarkandfire have the same name and are both 16
Hi, I'm Kareem. I'm 16.
Yup.
years old. 😛
What are the odds on that?
Originally posted by wolfgang59I'm inclined to agree with you: Car A is going 60; Car B is going 40. Seems pretty simple all right.
Regardless of their accelerations the current fastest car will pull ahead.
Originally posted by Tatanka YotankaThats the police officers velocity when they have traveled equal distances. If the police officer speed is constant after v=120 he will never catch the speeder.
I'm inclined to agree with you: Car A is going 60; Car B is going 40. Seems pretty simple all right.
As to the police question: It was stated that the car going 120 never alters his speed so why would he be going 240 when caught? The posted answer seems to be x2. With a constant acceleration of 10 kph/s it will take 12 seconds to reach 120 kph.
Originally posted by joe shmoYou guys make this stuff way too hard to explain. Much simpler answer:
Thats the police officers velocity when they have traveled equal distances. If the police officer speed is constant after v=120 he will never catch the speeder.
Originally posted by joe shmoThat's true, and it did occur to me after going to bed and I contemplated getting up and noting that. I didn't.
Thats the police officers velocity when they have traveled equal distances. If the police officer speed is constant after v=120 he will never catch the speeder.
Originally posted by clandarkfirethere is incomplete data here. since what is being asked involves distance, there is no way to calculate it without first knowing the distance between the two at the time the pursuit is begun.
But as far as I can see, Joe Shmo is right.
Next:
A speeding motorist travels past a stationary police officer at a speed of 120km/hr. The officer immediately begins pursuit at a constant acceleration of 10km/hr/s.
a. How long will it take for the police officer to reach the speeder, assuming the speeder maintains a constant speed?
b. How fast will the officer be traveling at that time?
Originally posted by kyletoybitsthere is no reference to distance in the question.
there is incomplete data here. since what is being asked involves distance, there is no way to calculate it without first knowing the distance between the two at the time the pursuit is begun.