- 02 May '03 22:43

-( (3/3) - 3) = 3*Originally posted by villa68***1 1 1=3**

2 2 2=3

3 3 3=3

4 4 4=3

5 5 5=3

6 6 6=3

7 7 7=3

8 8 8=3

9 9 9=3

using just things from a scientific calculator make all of the above maths equations true

eg

1+1+1=3

2+(2/2)=3

(?4) / (?4) + (?4) = 3

-( cos(5!) * 5 + cos(5!) ) = 3

cos(6!) + cos(6!) + cos(6!) = 3

cos(7!) + cos(7!) + cos(7!) = 3

cos(8!) + cos(8!) + cos(8!) = 3

-( ( (?9) / (?9) ) - (?9) ) = 3 OR cos(9!) + cos(9!) + cos(9!) = 3

Is that what you were looking for? - 02 May '03 23:47

The "?" are supposed to be the squareroot sign.*Originally posted by Crowley***-( (3/3) - 3) = 3**

(?4) / (?4) + (?4) = 3

-( cos(5!) * 5 + cos(5!) ) = 3

cos(6!) + cos(6!) + cos(6!) = 3

cos(7!) + cos(7!) + cos(7!) = 3

cos(8!) + cos(8!) + cos(8!) = 3

-( ( (?9) / (?9) ) - (?9) ) = 3 OR cos(9!) + cos(9!) + cos(9!) = 3

Is that what you were looking for? - 07 May '03 18:53

but where do all the zero's come from? I'd assume the only numbers allowed would be the three defined. by the way, for 9,9,9, there's*Originally posted by villa68***the simplist answer is**

to put everything to the power of 0

cos everything to the power of 0 is 1

square_root( 9 * 9 ) / square_root( 9 )