simple maths

1 1 1=3
2 2 2=3
3 3 3=3
4 4 4=3
5 5 5=3
6 6 6=3
7 7 7=3
8 8 8=3
9 9 9=3

using just things from a scientific calculator make all of the above maths equations true

eg
1+1+1=3
2+(2/2)=3

Originally posted by villa68
1 1 1=3
2 2 2=3
3 3 3=3
4 4 4=3
5 5 5=3
6 6 6=3
7 7 7=3
8 8 8=3
9 9 9=3

using just things from a scientific calculator make all of the above maths equations true

eg
1+1+1=3
2+(2/2)=3

-( (3/3) - 3) = 3
(?4) / (?4) + (?4) = 3
-( cos(5!) * 5 + cos(5!) ) = 3
cos(6!) + cos(6!) + cos(6!) = 3
cos(7!) + cos(7!) + cos(7!) = 3
cos(8!) + cos(8!) + cos(8!) = 3
-( ( (?9) / (?9) ) - (?9) ) = 3 OR cos(9!) + cos(9!) + cos(9!) = 3

Is that what you were looking for?

Originally posted by Crowley
-( (3/3) - 3) = 3
(?4) / (?4) + (?4) = 3
-( cos(5!) * 5 + cos(5!) ) = 3
cos(6!) + cos(6!) + cos(6!) = 3
cos(7!) + cos(7!) + cos(7!) = 3
cos(8!) + cos(8!) + cos(8!) = 3
-( ( (?9) / (?9) ) - (?9) ) = 3 OR cos(9!) + cos(9!) + cos(9!) = 3

Is that what you were looking for?

The "?" are supposed to be the squareroot sign.

How about:
3 + 3 - 3 = 3
4 - (4/4) = 3

Originally posted by godzillion
How about:
3 + 3 - 3 = 3
4 - (4/4) = 3

Probably a tad simpler innit...

the simplist answer is

to put everything to the power of 0
cos everything to the power of 0 is 1

🙂

Originally posted by villa68
the simplist answer is

to put everything to the power of 0
cos everything to the power of 0 is 1

🙂

but where do all the zero's come from? I'd assume the only numbers allowed would be the three defined. by the way, for 9,9,9, there's
square_root( 9 * 9 ) / square_root( 9 )

but when you don't enter a number, does it not usually take it to be 0?

Originally posted by genius
but when you don't enter a number, does it not usually take it to be 0?

Not on a scientific calculator. or not on mine at least. When you hit the 'x to power y' button, there isn't a default y.