Originally posted by Ponderable
So I Need clarification:
Winning combination is A+K or A+Q or A+J or K+A or Q+A or J+ A. All other combinations lose, right? or is K+K+A (QQA, JJA) also winning?
The actual Point of your question is that you compare apples to oranges. Before you know that the Ace is the ace of hearts you have 15 Cards left and 12 of those win. If you know the Suite ...[text shortened]... The number of winning combinations given by you with 48 from 54 outcomes is false to begin with.
Just two cards (keep it simple)
Hands containing at least one ace are:
A & picture card (4*12) = 48
2 aces (4*3)/2 = 6
You must have one of these two types if you know you have one ace.
No other possibilities.