1. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
    Joined
    28 Dec '04
    Moves
    53223
    11 Apr '10 16:25
    You have several versions of mirrors, each facing it's opposite in pairs, 1 degree offset from parallel. One set is 90% reflective, another 99% reflective. They are both front surface mirrors so there won't be double reflections. There is also a candle 1 cm wide in the center of each set. You observe there are multiple reflections but they all start bearing right. The 90% mirror reflects 20 times before you can't see the next reflection.
    The 99% job reflects 100 times before you can't see the next reflection.
    In both cases, how far apart are the images, that is to say, what is the horizontal spread of the images since each one is slightly offset from the last.
  2. Joined
    11 Nov '05
    Moves
    43938
    11 Apr '10 17:12
    Originally posted by sonhouse
    The 99% job reflects 100 times before you can't see the next reflection.
    If 99% of the light remains for each reflection, then after 100 reflections there will remain 0.99^100 = 36.6% of the original light.
  3. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
    Joined
    28 Dec '04
    Moves
    53223
    11 Apr '10 23:01
    Originally posted by FabianFnas
    If 99% of the light remains for each reflection, then after 100 reflections there will remain 0.99^100 = 36.6% of the original light.
    Which should be plenty enough left to see. But I am after the horizontal spread of the reflections.

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