what's the msot ingenious method of finding square roots that you have come accross?

if you take a pendulum and measure the time for x swings, then half the length and measure the time for x swings, then divide the first time by the second - you have 3^(1/2) ! (that's an exclamation mark, not a factorial by the way...)

to find root 3, third the length, root 4 quater it etc...! although it only works accuratly without dampening i think...anwyay, anyone got any more random ways?...

Originally posted by genius what's the msot ingenious method of finding square roots that you have come accross?

if you take a pendulum and measure the time for x swings, then half the length and measure the time for x swings, then divide the first time by the seco ...[text shortened]... ut dampening i think...anwyay, anyone got any more random ways?...

Wow. That is amazing.

The only one I can think of is by measuring the long side of an isosceles right triangle.

Do we need a pendulum (whose accuracy depends on theta)?

Drop an apple from a tree.
Drop it again from another tree twice as big/small.
Divide one time by the other.
(Of course, wind resistance will be a factor.)

Do we need a pendulum (whose accuracy depends on theta)?

Drop an apple from a tree.
Drop it again from a another tree twice as big/small.
Divide one time by the other.
(Of course, wind resistance will be a factor.)

This sounds like a lot of tree climbing ðŸ™‚ ðŸ™‚ ðŸ™‚

you could just look at the formula for the time period of a pendulum and you'd know that anyway. the best way of finding square roots is using matrices.

Originally posted by valdez you could just look at the formula for the time period of a pendulum and you'd know that anyway. the best way of finding square roots is using matrices.

How do you use matrices to find square roots? Sounds interesting.

Do we need a pendulum (whose accuracy depends on theta)?

Drop an apple from a tree.
Drop it again from another tree twice as big/small.
Divide one time by the other.
(Of course, wind resistance will be a factor.)