27 Aug '10 23:55>
How would a steel ball filled with mercury - no bubbles - act in a pinball machine?
Originally posted by AThousandYoungIf you take two eggs, one hard boiled and one not cooked, try spinning them. The hard boiled egg will spin but the one not cooked will refuse to spin due to internal friction of the liquid. I suspect there would be a similar reaction to your ball. It would probably not even roll at the same speed as a solid metal ball, would probably be sluggish in its roll so might not even activate those sensors based on the rubber string where it hits and a solenoid strikes it to send it elsewhere.
How would a steel ball filled with mercury - no bubbles - act in a pinball machine?
Originally posted by mortisdeadYou probably have seen how fast those balls are going when they hit the sensor/barrier/kicker mechanism. If there was mercury inside, it might not go fast enough to trigger them.
sounds about right, apart from not activating the sensors, as long as the ball has enough velocity then the force is the same.
you'd lose the stability of a spinning sphere so the path it travels would not be as straight.
interesting question 🙂
Originally posted by sonhouseAccording to Newton the speed does not determine the force, the accelleration does.
You probably have seen how fast those balls are going when they hit the sensor/barrier/kicker mechanism. If there was mercury inside, it might not go fast enough to trigger them.
I guess the pressure needed could be made less or more though.
Originally posted by TheMaster37Yes there is the old standard F=MA and such but we are talking about kinetic energy, Ke=MV^2 here. There has to be a certain amount of kinetic energy to activate the sensor, like those kid's clicker toys where you flex this curved metal piece and it takes a certain amount of flexing to make it click, anything less and nothing happens.
According to Newton the speed does not determine the force, the accelleration does.
Just trying to sound smart 😛
Originally posted by sonhouseSO we lose x amount of energy due to the inertia of the mercury, we lose y amount of stability (can we quantify this?) and the end product is a ball with y speed with the energy reduced by the inertia so less likely to interact with sensors but if you hit it hard enough it will be enough for the first few bounces, assuming that it can be aimed because of y.
Yes there is the old standard F=MA and such but we are talking about kinetic energy, Ke=MV^2 here. There has to be a certain amount of kinetic energy to activate the sensor, like those kid's clicker toys where you flex this curved metal piece and it takes a certain amount of flexing to make it click, anything less and nothing happens.
Originally posted by mortisdeadless energy I'd say ...
marginally softer so greater deformation, but also denser so more energy; will they balance out? perhaps yes, perhaps no.
Originally posted by wolfgang59So can we chart the basics of a steel ball filled with mercury on Excel, where you take a basically frictionless surface, say optically smooth glass flat and take a all steel ball and tip one end of the surface to cause a ramp.
less energy I'd say ...
assuming the force from the flipper is constant the lead ball will have a smaller velocity than the steel ball (in ratio to relative densities)
the velocity squared element of the balls' KE will mean the stell ball has more energy.
(I think ...) 😕
Originally posted by sonhouseAh, but an egg is not a sphere, the egg has much more resistance with the liquid inside.
If you take two eggs, one hard boiled and one not cooked, try spinning them. The hard boiled egg will spin but the one not cooked will refuse to spin due to internal friction of the liquid. I suspect there would be a similar reaction to your ball. It would probably not even roll at the same speed as a solid metal ball, would probably be sluggish in its roll ...[text shortened]... sensors based on the rubber string where it hits and a solenoid strikes it to send it elsewhere.