1. Standard memberAThousandYoung
    Shoot the Squatters?
    tinyurl.com/43m7k8bw
    Joined
    23 Aug '04
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    26660
    04 Oct '07 19:30
    Originally posted by ranjan sinha
    Did you google it up to find this out?
    😵
  2. H. T. & E. hte
    Joined
    21 May '04
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    3510
    06 Oct '07 18:32
    ?? was googling of any help?😵😲
  3. Joined
    25 Jul '04
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    3205
    11 Oct '07 07:52
    Originally posted by howzzat
    No..not at all..Here is my proof which is much much shorter than the one given in ranjan's post dated 29 th Sept. Borrowing the notations and symbols in that post, the area of the pentagon ABCDE is:-
    w = Ar. of tr.ABC + Ar. of tr. ADE + Ar. of tr. ACD.
    = x + x + (AC/SC)*x. =(2 + c)*x where c = AC/SC..............eqn.(1)
    [AC/SC is the rati ...[text shortened]... and (2) we get 2+c = 3+1/c; hence c = {sqrt(5) +1}/2
    Thus we get the required value of w/x.
    Well done Howzzat. Your solution is far more elegant than the one provided by the poser.
  4. Joined
    25 Jul '04
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    3205
    11 Oct '07 07:563 edits
    Originally posted by ranjan sinha
    Did you google it up to find this out?
    Googling is of no help for finding solutions to puzzles. After seeing this pentagon puzzle here, I found it quite challenging and interesting. I posted this puzzle on a site dedicated to "cutting the Gordian Knot" for the wider mathematical community.
  5. Joined
    25 Jul '04
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    3205
    11 Oct '07 07:592 edits
    Originally posted by HolyT

    Speaking of cheating, someone here is trying to find the answer by posting it in another forum: http://www.cut-the-knot.org/htdocs/dcforum/DCForumID6/648.shtml
    No cheating.. See the post above. I posted this puzzle on that site with a view to expose it to a wider interested audience.
  6. at the centre
    Joined
    19 Jun '04
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    3257
    13 Oct '07 11:40
    Originally posted by sarathian
    Well done Howzzat. Your solution is far more elegant than the one provided by the poser.
    thx for the compliments ..
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