So its 100 years from now, Fedex has a space division, rockets can go for hours at many g's and there is an emergency on the moon, they have to get this medicine to the moon in one hour or 50 people die from a horrible lunar virus.

So if you can accelerate at some steady g force, then half way turn around and decel the rest of the way to be at the moon with zero velocity, soft landing, how many g's of constant acceleration to get that medicine to the moon in one hour does it take?

Originally posted by sonhouse So its 100 years from now, Fedex has a space division, rockets can go for hours at many g's and there is an emergency on the moon, they have to get this medicine to the moon in one hour or 50 people die from a horrible lunar virus.

So if you can accelerate at some steady g force, then half way turn around and decel the rest of the way to be at the moon ...[text shortened]... how many g's of constant acceleration to get that medicine to the moon in one hour does it take?

about 12g
(that's using my left hand and the back of an envelope)

basically you need to know the acceleration needed to get half way (200,000 km) in 30 mins

Originally posted by wolfgang59 about 12g
(that's using my left hand and the back of an envelope)

basically you need to know the acceleration needed to get half way (200,000 km) in 30 mins

my estimate is surprisingly low ... ðŸ˜•

I got about 12.25, you were pretty close. I was wondering if we ever develop propulsion that powerful how much long term acceleration could a person take?

Obviously 12 g's would kill you but could you take it for an hour? I don't think so.

1 g would get you there in a few hours however, so that is possible.

2g's? maybe.

The formula is T= square root of (2S/A) T=time, S=distance, A=acceleration.