A Ferrari Testarossa is 4485 mm long and 1130 mm wide. It's taken to a track and field area where the field inside the track consists of a square in the middle and two semicircles at the ends, with a total perimeter length of 400 meters. How wide does the track need to be for the car to be able to go a full lap?
Are we to assume there is a wall on the inside and outside perimeter of the track, that the car is a perfect rectangle, and that the car's turning radius is irrelevant?
nice work, and yes, the 400 meters is as you wrote it, and yes, I thought that the Ferrari looks like a moving rectangle when seen from above, either with four-wheel steering or with a very slippery track and no steering needed at all.
I didn't use trigs.
Distance from the center of the semicircle to the middle of left side of the car (if driving counter-clockwise) = R.
Distance from the center of the semicircle to the right front / back corner = ((R+w)^2+(L/2))^(1/2)
So the width is of the track is ((R+w)^2+(L/2))^(1/2) - R.