05 Apr 05
3 edits
Originally posted by Mephisto2This is a beautiful masterpiece. A pity that the first move is so obvoius:
[fen]8/3b4/k2p3P/1p1K3P/1P4r1/8/3R4/8/ w[/fen]
white to play and win
1.h7 Rg5+ 2.Kxd6 Rxh5 3.Kc7! Be6 4.Kb8! and wins (5.Rd6# )
EDITED:
Hmmm...my mistake. I've missed
4...Bd5! 5.Rxd5 Rxd5 6.h8R!! (6.h8Q? Rd8+! 7.Qxd8 stalemate) 6...Rd6 7.Kc7! and wins.
05 Apr 05
Originally posted by ilywrincorrect. As the title says, Troitski developed this minor promotion puzzle based on the Saavedra position.
This is a beautiful masterpiece. A pity that the first move is so obvoius:
1.h7 Rg5+ 2.Kxd6 Rxh5 3.Kc7! Be6 4.Kb8! and wins (5.Rd6# )
EDITED:
Hmmm...my mistake. I've missed
4...Bd5! 5.Rxd5 Rxd5 6.h8R!! (6.h8Q? Rd8+! 7.Qxd8 stalemate) 6...Rd6 7.Kc7! and wins.
05 Apr 05
1 edit
The small number of possible moes makes it a little clearer, I'll have a shot.
Can't be a pawn move, either way the rook will take both of them without a problem.
A king move and then Kxa2, so it can't be that.
So the knight to move, and looks to be Nc1.
If Rxb5, then white can safely advance the c-pawn, moving the rook back to the c-file sees Nb3+
If Kb2, then Nd3+
If Kb1 then white can play Kd2, next king move and the knight moves to fork both black pieces again.
If black takes the pawn (after Kd2), I'm a little stuck there.
05 Apr 05
Originally posted by Peakite1.Nc1 Rxb5 2.c7 what if now black plays Rd5+?
The small number of possible moes makes it a little clearer, I'll have a shot.
Can't be a pawn move, either way the rook will take both of them without a problem.
A king move and then Kxa2, so it can't be that.
So the knight to move, and looks to be Nc1.
If Rxb5, then white can safely advance the c-pawn, moving the rook back to the c-file sees ...[text shortened]... fork both black pieces again.
If black takes the pawn (after Kd2), I'm a little stuck there.
05 Apr 05
Originally posted by Peakiteof course, I was mixing things up. I meant, what if black plays Rd4 (not Rd5). To make sure, we are talking 1Nc1 Rxb5 2.c7 Rd5+ 3.Nd3 Rxd3 4.Kc2 Rd4.
c8=Q
........ Ra5
Qh8+ Ka2
Qb2++
........ Rc5+
Qxc5
........ Rd2+
Kxd2
........ Rd8
Qa6++
........ Kb2 or any other rook move
Qa8+/++ mate next move if not immediate
And once you answered that, what happens if black plays Rd5 (this time it is d5) after white's first move: 1.Nc1 Rd5+ (he doesn't take on b5).?
06 Apr 05
Originally posted by Peakitea) "The second one after Rd5+ Nd3 and play out as in the first, but white may have the extra pawn, making any win easier."
The second one after Rd5+ Nd3 and play out as in the first, but white may have the extra pawn, making any win easier.
5. Kb3 Rd3+ 6. Kc2 R(any) 7. c8=Q
if 5. Kc3 Rd1 6. Kc2 Rd4 and it's back to the same position
Don't think so: 1.Nc1 Rd5 2.Nd3? Rxd3+ 3.Kc2 Rd5 and now if
4.c7 then Rc5+ followed by Rxc7 is enough for draw (at least)
or if 4.Kc2 then simply Rxb5 is enough for draw.
You have to find a different response to 1.Nd3 Rd5 to win
b) "35. Kb3 Rd3+ 6. Kc2 R(any) 7. c8=Q"
1.Nc1 Rxb5 2.c7 Rd5+ 3.Nd3 Rxd3 4.Kc2 Rd4! 5.Kb3? Rd3+ 6.Kc2 Rd4! 7.c8=Q? Rc4+! 8.Qxc4 stalemate
c) "if 5. Kc3 Rd1 6. Kc2 Rd4 and it's back to the same position"
1.Nc1 Rxb5 2.c7 Rd5+ 3.Nd3 Rxd3 4.Kc2 Rd4! 5.Kc3 Rd1+
yes, with the same result as under b) .
Still some work to do in both a) and b) variations. The a)-one is rather special