Try this puzzle from Geometry

ranjan sinha
Posers and Puzzles 12 Sep '07 13:55
1. 12 Sep '07 13:551 edit
ABC is an isosceles triangle with its vertex angle A equal to 20 degrees.
On the base BC make /_BCD = 60 degrees;point D lies on AB.
Take point E on AB such that BE=BC.
Take a point F on AC such that BF=BC (point F is not coincident with C).
Thus BC=BF=BE.
Prove that DE=CF.
2. 14 Sep '07 14:181 edit
BTW.. in the given isosceles triangle AB=AC.
And /_BAC=20 degrees.
3. 19 Sep '07 04:50
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4. 19 Sep '07 14:40
Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?
5. 20 Sep '07 06:50
Originally posted by CoolPlayer
Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?
Obviously F lies onAB in-between A and B.
6. 20 Sep '07 18:17
Originally posted by ranjan sinha
Obviously F lies onAB in-between A and B.
Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?
7. 23 Sep '07 08:12
Originally posted by HolyT
Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?
Exactly so.
8. 13 Oct '07 11:21
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9. 27 Oct '07 17:03
Originally posted by ranjan sinha
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Why not provide the proof ? Geometry problems are generally diecy..