Try this puzzle from Geometry

ABC is an isosceles triangle with its vertex angle A equal to 20 degrees.
On the base BC make /_BCD = 60 degrees;point D lies on AB.
Take point E on AB such that BE=BC.
Take a point F on AC such that BF=BC (point F is not coincident with C).
Thus BC=BF=BE.
Prove that DE=CF.

BTW.. in the given isosceles triangle AB=AC.
And /_BAC=20 degrees.

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Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?

Originally posted by CoolPlayer
Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?

Originally posted by ranjan sinha
Obviously F lies onAB in-between A and B.

Originally posted by HolyT
Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?

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Originally posted by ranjan sinha
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