1. H. T. & E. hte
    Joined
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    12 Sep '07 13:551 edit
    ABC is an isosceles triangle with its vertex angle A equal to 20 degrees.
    On the base BC make /_BCD = 60 degrees;point D lies on AB.
    Take point E on AB such that BE=BC.
    Take a point F on AC such that BF=BC (point F is not coincident with C).
    Thus BC=BF=BE.
    Prove that DE=CF.
  2. H. T. & E. hte
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    14 Sep '07 14:181 edit
    BTW.. in the given isosceles triangle AB=AC.
    And /_BAC=20 degrees.
  3. H. T. & E. hte
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    19 Sep '07 04:50
    🙄 🙄 🙄
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  4. Joined
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    19 Sep '07 14:40
    Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?
  5. H. T. & E. hte
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    20 Sep '07 06:50
    Originally posted by CoolPlayer
    Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?
    Obviously F lies onAB in-between A and B.
  6. San Diego
    Joined
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    20 Sep '07 18:17
    Originally posted by ranjan sinha
    Obviously F lies onAB in-between A and B.
    Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?
  7. H. T. & E. hte
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    23 Sep '07 08:12
    Originally posted by HolyT
    Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?
    Exactly so.
  8. H. T. & E. hte
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    13 Oct '07 11:21
    ????
    😳😀
  9. Joined
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    27 Oct '07 17:03
    Originally posted by ranjan sinha
    ????
    😳😀
    Why not provide the proof ? Geometry problems are generally diecy..
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