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Posers and Puzzles

H. T. & E. hte

Joined 21 May '04 Moves 3510 ABC is an isosceles triangle with its vertex angle A equal to 20 degrees.
On the base BC make /_BCD = 60 degrees;point D lies on AB.
Take point E on AB such that BE=BC.
Take a point F on AC such that BF=BC (point F is not coincident with C).
Thus BC=BF=BE.
Prove that DE=CF.

H. T. & E. hte

Joined 21 May '04 Moves 3510 BTW.. in the given isosceles triangle AB=AC.
And /_BAC=20 degrees.

H. T. & E. hte

Joined 21 May '04 Moves 3510 ðŸ™„ ðŸ™„ ðŸ™„
ðŸ˜² ðŸ˜²
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Joined 30 Oct '04 Moves 2295 Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B?

H. T. & E. hte

Joined 21 May '04 Moves 3510 Originally posted by CoolPlayer
Does the point F lie in-between A and B on AB? Or does it lie on the projected line AB , beyond B? Obviously F lies onAB in-between A and B.

San Diego

Joined 23 May '07 Moves 2124 Originally posted by ranjan sinha
Obviously F lies onAB in-between A and B. Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right?

H. T. & E. hte

Joined 21 May '04 Moves 3510 Originally posted by HolyT
Wait--you mean that F lies on AC between A and C, right? D and E lie on AB, between A and B, right? Exactly so.

H. T. & E. hte

Joined 21 May '04 Moves 3510

Joined 25 Jul '04 Moves 3205 Originally posted by ranjan sinha
????
ðŸ˜³ðŸ˜€ Why not provide the proof ? Geometry problems are generally diecy..